Question

An expanding gas does 153 J of work on its surroundings at a constant pressure of 1.01 atm. If the gas initially occupied 68.0 mL, what is the final volume of the gas?

Answer 1

Answer:

69.5mL

Explanation:

We are given that

Work done by gas on surroundings=w=153 J=$\frac{153}{101.3}Latm$

1Latm=101.3J

Pressure =P=1.01atm

Initial volume of gas=68 mL

We have to find the final volume of the gas.

We know that

Work done on constant pressure

$w=P\Delta V=P(V_2-V_1)$

Using the formula

$\frac{153}{101.3}=1.01(V_2-68)$

$V_2-68=\frac{153}{101.3\times 1.01}=1.5$

$V_2=68+1.5=69.5mL$

Hence, the final volume of gas=69.5mL