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viva [34]
3 years ago
9

An expanding gas does 153 J of work on its surroundings at a constant pressure of 1.01 atm. If the gas initially occupied 68.0 m

L, what is the final volume of the gas?
Physics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

69.5mL

Explanation:

We are given that

Work done by gas on surroundings=w=153 J=\frac{153}{101.3}Latm

1Latm=101.3J

Pressure =P=1.01atm

Initial volume of gas=68 mL

We have to find the final volume of the gas.

We know that

Work done on constant pressure

w=P\Delta V=P(V_2-V_1)

Using the formula

\frac{153}{101.3}=1.01(V_2-68)

V_2-68=\frac{153}{101.3\times 1.01}=1.5

V_2=68+1.5=69.5mL

Hence, the final volume of gas=69.5mL

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Answer:

ExplanaThis is a way of measuring how much gravity there is. The formula is: weight/mass = gravitational field strength.

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Here on Earth, if I jump I am pulled back to ground by gravity. What is my weight? My mass is 80kg and if we multiply by gravitational field strength (10N/kg) - my weight is 800N. Now if I go to the moon, my mass will be the same, 80kg. We multiply that by the moon's gravitational field strength, which is 1.6 N/ kg. That means my weight on the moon is 128N. So I have different weights on the Earth and on the Moon. That's why astronauts can jump high into the air on the moon - they're lighter up there.

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2 years ago
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A science class puts a balloon containing 1.25 l of air at 101 kpa into a bell jar. using an air pump, the class removes some of
storchak [24]
The first thing you should know in this case is the following definition:
 PV = nRT
 Then, as the temperature is constant, then:
 PV = k
 Then, we have two states:
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 Substituting the values:
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Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50 μm2. Convert this
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1 m = 1 000 000 ym

converted other way we can say that:

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