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viva [34]
3 years ago
9

An expanding gas does 153 J of work on its surroundings at a constant pressure of 1.01 atm. If the gas initially occupied 68.0 m

L, what is the final volume of the gas?
Physics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

69.5mL

Explanation:

We are given that

Work done by gas on surroundings=w=153 J=\frac{153}{101.3}Latm

1Latm=101.3J

Pressure =P=1.01atm

Initial volume of gas=68 mL

We have to find the final volume of the gas.

We know that

Work done on constant pressure

w=P\Delta V=P(V_2-V_1)

Using the formula

\frac{153}{101.3}=1.01(V_2-68)

V_2-68=\frac{153}{101.3\times 1.01}=1.5

V_2=68+1.5=69.5mL

Hence, the final volume of gas=69.5mL

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A negative charge of -2.0 C and a positive charge of 3.0 C are separated by 80 m. What is the electrostatic force between the tw
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Answer:

1. 8437500 N

2. The force between the two charges is attractive.

Explanation:

1. Determination of the force between the two charges.

Charge 1 (q₁) = –2.0 C

Charge 2 (q₂) = 3.0 C

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F = 8437500 N

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2. From the question given, the charges are:

Charge 1 (q₁) = –2.0 C

Charge 2 (q₂) = 3.0 C

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To determine the height of a tall building such as Sears Tower in Chicago, Illinois a ball was dropped from the top of the build
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Answer:

The height of Sears Tower is 1448.5 feet.

Explanation:

<h3>We apply the free fall formula to the ball: </h3><h3>y=v_{o} *t+\frac{1}{2} *g*t^{2}</h3><h3>y: The vertical distance the ball moves at time t  </h3><h3>v_{o}i: Initial speed </h3><h3>g=Gravity acceleration=9.8*(\frac{\frac{1ft}{0.305m} }{s^{2} } )</h3>

Known information

We know that the vertical distance (y) that the ball moves in 9,5s  is equal to height of Sears Tower (h).  

Too we know that the ball is released from rest, then,v_{0}=0

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We replace  in the equation 1 the data following;

y=h

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g=32,1\frac{ft}{s^{2} }

t= 9,5s

h=0*9.5+\frac{1}{2} *32.1*9.5^{2}

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