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3 years ago

Based on your answers to parts a, b, and c select the best lewis structure (electron-dot structure) for hoi.

Chemistry

1 answer:

vodomira [7]3 years ago

6 0

Answer : The lewis dot structure includes the lone pair of electrons in any element and is helpful for defining the bond formation using the electrons.

In the molecule of HOI hydrogen is to the left of oxygen; oxygen is in middle and Iodine is at right of oxygen.

The picture is attached for better understanding.

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Calculate the amount of energy when water at 72 degrees c freezes completely at 0 degrees c

gtnhenbr [62]

Answer:

The amount of energy needed when water at 72 degrees c freezes completely at 0 degrees c is $6.37\times10^4$ Joules

Explanation:

$Q = m \times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

$Q_{1}=100 g \times 4.184 \frac{J}{g^{\circ} \mathrm{C}} \times\left(72^{\circ} \mathrm{C}-0^{\circ} \mathrm{C}\right)$

$Q_1$ =30125J

Q is the heat energy in Joules

c is the specific heat capacity (for water 1.0 cal/(g℃)) or 4.184 J/(g℃)

m is the mass of water

mass of water is assumed as 100 g (since not mentioned)

$Q_2$ is the heat energy required for the phase change

$Q_2$ =mass × heat of fusion

$\\$Q_{2}=100 g \times 336 \frac{J}{g}$\\\\$Q_{2}=33600 J$$

Total heat = $Q_1 + Q_2$

Total Heat = 30123J + 33600J

= 63725 J

= $6.37\times10^4$ Joules is the answer

3 0

3 years ago

_KCIO, - __KCI + ___02

sweet [91]

Answer:

2,2,1

Explanation:

3 0

2 years ago

When a gas is cooled at constant pressure, what happens to its molecules and volume?

Dima020 [189]

Assuming it's a perfect gas, we have PV=nRT hence if T goes down, V goes down up. The volume will decrease.

3 0

3 years ago

Which of these is the smallest volume 500mL, 2,500 cm3, 5.5•10-1, 25 m3

mezya [45]

25m³.
500mL = 500cm³
25m³ = 2,500cm³
5.5x9 = 49.5(cm³)
25m³ is the smallest among the others.

5 0

3 years ago

In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?

Oksanka [162]

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In $H_2O$ , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in $Cl^-$ is -1. On product side, the oxidation number of hydrogen in $H_2$ is zero and in $OH^-$ the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in $Cl_2$ is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

8 0

3 years ago