Based on your answers to parts a, b, and c select the best lewis structure (electron-dot structure) for hoi.
1 answer:
Answer : The lewis dot structure includes the lone pair of electrons in any element and is helpful for defining the bond formation using the electrons.
In the molecule of HOI hydrogen is to the left of oxygen; oxygen is in middle and Iodine is at right of oxygen.
The picture is attached for better understanding.
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Answer:change in energy of the electron=3.052x 10^-19J
which energy level does it move= level 2 , n=2
Explanation:
Using the formulae
1/λ = R (1/n1²- 1/n2²)
Where λ= 656.27 nm
1 nm = 1 x 10^-9 m
656.27 nm = 656.27 x 1 x 10^-9 =6.5726 x 10^-7
R =Rydberg constant = 1.0967 x 10^7m-1
1/λ = R (1/n1²- 1/n2²)
1/6.5726 x 10^-7=1.0967 x 10^7(1/n1²- 1/3²)
1/n1²=(1/6.5726 x 10^-7 x 1/1.0967 x 10^7) + 1/9
1/n1²=1,521,467.9 x 9.118x10^-8 + 0.1111
1/n1² =0.2498
n1²= 1/0.2498 =4
n1= = 2
it moves to energy level 2
b) Change in energy =ΔE = Rhc (1/n1²- 1/n2²)
Where R==Rydberg constant = 1.0967 x 10^7m-1
h = Planck constant = 6.626x 10^-34js
c = speed of light = 3.0 x 10^8 x m/s
ΔE = Rhc (1/n1²- 1/n2²)
=1.0967 x 10^7m-1 x6.626x 10^-34js X 3.0 x 10^8 x m/s (1/2² - 1/3²)
=2.18 x 10-18 x ( 1 /4 - 1/9)
=3.052x 10^-19J