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goldfiish [28.3K]
3 years ago
6

A piece of work can be finished in 30 days 8 hours a day. In how many Days the work would have been finished working 6 hours a d

ay
​
Chemistry
1 answer:
goblinko [34]3 years ago
7 0

Answer:

If 8 hours= 30 days

then 6 hours= 8×30÷6

                    = 40 days

Explanation:

You might be interested in
Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

3 0
2 years ago
What are the differences between HDL and LDL?​
il63 [147K]

Answer:

LDL is

low density lipid

HDL is

high density lipid

Explanation:

HDL helps rid your body is excess cholesterol so so it won't end up in your arteries

LDL is also called "bad cholesterol" because it takes cholesterol to your arteries

6 0
3 years ago
By how much will the water temperature increases if 1046 J of heat energy are added. The specific heat of water is 4.184 J/g • °
Brilliant_brown [7]

Answer:

Option A

250 degrees Celcius

Explanation:

If 1046J of heat energy is added to water, the water will experience a rise in temperature, at a rate that is directly proportional to its specific heat capacity.

Mathematically, this can be seen as Q=C\Delta T

Where C = specific heat of water = 4.184 J/g • °C.

Q = heat energy = 1046 J

\Delta T =1046/4.148=250 degrees Celcius

Therefore, the increase in temperature that will be experienced, is for 250 degrees Celcius

8 0
2 years ago
Determine the number of moles of water assicated with the salt.
Nookie1986 [14]

Answer:

Divide the mass of your anhydrous (heated) salt sample by the molar mass of the anhydrous compound to get the number of moles of compound present. In our example, 16 grams / 160 grams per mole = 0.1 moles. Divide the mass of water lost when you heated the salt by the molar mass of water, roughly 18 grams per mole.In order to determine the formula of the hydrate, [Anhydrous Solid⋅xH2O], the number of moles of water per mole of anhydrous solid (x) will be calculated by dividing the number of moles of water by the number of moles of the anhydrous solid (Equation 2.12. 6).

6 0
2 years ago
A sample of an unknown liquid has a volume of 24.0 mL and a mass of 6 g. What is its density? Show your work or explain how you
kobusy [5.1K]
The answer would be 0.25 g/mL. 
I determined the density by dividing the mass by the volume which gives you the density. D = mass/volume.
<span>6 g / 24 mL = 0.25 g/mL </span>
8 0
2 years ago
Read 2 more answers
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