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goldfiish [28.3K]
3 years ago
6

A piece of work can be finished in 30 days 8 hours a day. In how many Days the work would have been finished working 6 hours a d

ay
​
Chemistry
1 answer:
goblinko [34]3 years ago
7 0

Answer:

If 8 hours= 30 days

then 6 hours= 8×30÷6

                    = 40 days

Explanation:

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Answer: It has 52 protons
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Jayne's science teacher mixed a clear liquid with a blue liquid in a beaker. After a few minutes there was a white solid at the
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Jayne's science teacher mixed a clear liquid with a blue liquid in a beaker. After a few minutes there was a white solid at the bottom of the beaker.So,<span>It is a new substance with different properties.</span>
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3 years ago
What would be the mass of 3 moles of water molecules?
ankoles [38]

Answer:

\boxed {\boxed {\sf A. \ 54 \ grams }}

Explanation:

To convert from moles to grams, we must use the molar mass.

Recall that water's molecular formula is H₂O. It contains hydrogen and oxygen. Look up the two elements masses on the Periodic Table.

  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 15.999 g/mol

Now, use these masses to find water's mass. The subscript of 2 tells us there are 2 atoms of hydrogen, so we multiply hydrogen's mass by 2 and add oxygen's.

  • H₂O= 2(1.008 g/mol) + 15.999 g/mol = 18.015 g/mol

Use the molar mass as a ratio.

\frac{18.015 \ g \ H_2 O}{ 1 \ mol \ H_2 O}

Multiply by the given number of moles.

3 \ mol \ H_2O*\frac{18.015 \ g \ H_2 O}{ 1 \ mol \ H_2 O}

The moles of water will cancel.

3 *\frac{18.015 \ g \ H_2 O}{ 1 }

3 *{18.015 \ g \ H_2 O}

54.045 \ g \ H_2O

Round to the nearest whole number. The 0 in the tenth place tells us to leave the number as is.

54 \ g \ H_2O

There are about <u>54 grams</u> of water in 3 moles.

7 0
3 years ago
Read 2 more answers
Fifteen points! Nothing like chemistry quizzes in the morning... &gt;o&lt;
sertanlavr [38]

Answer:

Explanation:

HA(aq)+H2O(l)⟺H3O+(aq)+A−(aq)(1)

you need to solve for the Ka value. To do that you use

Ka=[H3O+][A−][HA](2)

Another necessary value is the pKa value, and that is obtained through pKa=−logKa

The procedure is very similar for weak bases. The general equation of a weak base is

BOH⟺B++OH−(3)

Solving for the Kbvalue is the same as the Ka value. You use the formula  

Kb=[B+][OH−][BOH](4)

The pKb value is found through pKb=−logKb  

The Kw value is found withKw=[H3O+][OH−].  

Kw=1.0×10−14(5)

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