All categories

3 years ago

PLSSS HELP ASAPPPPPP

Mathematics

1 answer:

Maslowich3 years ago

7 0

it will be A.25

Step-by-step explanation:

hope its right

You might be interested in

Solve this inequality j/4-8<4

ivann1987 [24]

I hope this helps you

j/4 <4+8

j/4 <12

j <12.4

j <48

7 0

3 years ago

Can you answer this, downstream and upstream word problem

tensa zangetsu [6.8K]

Its kinda blurry!!!!!

7 0

3 years ago

Someone pls help solve this

Inessa [10]

S = 3/5 or 0.6
explanation
-4/0.8 = 2/s-1
divide the numbers on the left: -5 = 2/s-1
multiply both side by s-1: -5(s-1)=2
simplify: -5s + 5 =2
gather like terms: -5s= 2 - 5
simplify: -5s= -3
divide both sides by -5: x=3/5

8 0

3 years ago

Identify the function that contains the data in the following table: x -2 0 2 3 5 f(x)

Veseljchak [2.6K]

Answer:

f(x) = |x - 2| + 1

Step-by-step explanation:

When x = -2, then f(-2) = 5

The first function gives the relation equation as f(x) = |x| + 1

So, f(-2) = |-2| + 1 = 2 + 1 = 3 ≠ 5

{Since the definition of |x| is given by

|x| = x, when x ≥ 0 and |x| = - x, when x < 0}

Again, the second function gives the relation equation as f(x) = |x - 2|.

So, f(-2) = |-2 - 2| = |-4| = 4 ≠ 5

Now, the third function gives the relation equation as f(x) = |x - 2| - 1.

So, f(-2) = |-2 - 2| - 1 = |-4| - 1 = 4 - 1 = 3 ≠5

Again, the fourth function gives the relation equation as f(x) = |x - 2| + 1.

Hence, f(-2) = |-2 - 2| + 1 = |-4| + 1 = 4 + 1 = 5

Therefore, the fourth function f(x) = |x - 2| + 1 contains the given data table.

For further clarity we can check f(0) = 3, f(2) = 1, f(3) = 2 and f(5) = 4. (Answer)

6 0

4 years ago

Read 2 more answers

If a Variable has a normal distribution with mean 30 and standard deviation 5 find the probability that the variable will be bet

Alexus [3.1K]

Answer:

P(25 < x < 37) = 0.77

Step-by-step explanation:

Given - If a Variable has a normal distribution with mean 30 and standard deviation 5

To find - find the probability that the variable will be between 25 and 37.

Proof -

Given that,

Mean, μ = 30

S.D, σ = 5

Now,

$z = \frac{x-\mu}{\sigma}$ ~ N(0,1)

Now,

P(25 < x < 37)

= $P(\frac{25 - 30}{5} < z < \frac{37 - 30}{5} )$

= P(1 < z < 1.4)

= P(z < 1.4) - P(z < -1)

= 0.9192 - 0.1587

= 0.7605

≈ 0.77

∴ we get

P(25 < x < 37) = 0.77

4 0

3 years ago

PLSSS HELP ASAPPPPPP​

PLSSS HELP ASAPPPPPP