Answer:
It means that person can do work or can posses energy at a rate of 550 watts.
Or : can posses energy of 550 joules in one second.
Explanation:
![{ \bf{power = \frac{work}{time} }}](https://tex.z-dn.net/?f=%7B%20%5Cbf%7Bpower%20%3D%20%20%5Cfrac%7Bwork%7D%7Btime%7D%20%7D%7D)
Answer:
<h2> 27m/s</h2>
Explanation:
Given data
initital velocity u=15m/s
deceleration a=3m/s^2
time t= 4 seconds
final velocity v= ?
Applying the expression
v=u+at------1
substituting our data into the expression we have
v=15+3*4
v=15+12
v=27m/s
The velocity after 4 seconds is 27m/s
Answer:
D). Field lines circle the Earth from east to west.
Explanation:
A microscopic force or gigantic magnetic field surrounds the Earth which functions as a force field that guards the planet against the radiations released from space. This magnetic field is characterized by the alignment of the North and South poles with the axis of rotation. Thus, the magnetic field lines of the Earth surround or circle of the Earth from East to West. Therefore, <u>option D</u> is the correct answer.
Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/
. The correct answer is 4.90 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.
Let M = 1kg and m = 3 kg
Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.
When the mass is released, the cart accelerates to the right can be calculated from Newton' second law of motion. That is,
M( g + a) = m(g - a)
1(9.8 + a) = 3( 9.8 - a)
9.8 +a = 29.4 - 3a
collect the like terms
4a = 19.6
a = 19.6/4
a = 4.9 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
Therefore, the cart accelerates to the right with a magnitude of 4.9 m/
. The correct answer is 4.90 m/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
Learn more about dynamics here: brainly.com/question/24994188
It depends on the type of question, mechanical condition and given values,
You can use the formula,
Coefficient of kinetic friction = Force of Kinetic friction / Normal force (perpendicular to contacting surfaces)
Hope this helps!