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Ludmilka [50]
3 years ago
9

A large ebony wood log, totally submerged, is rapidly floating down a flooded river. If the mass of the log is 165 kg, what is t

he buoyant force acting on the submerged log ?
Physics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

F = 1618.65[N]

Explanation:

To solve this problem we use the following equation that relates the mass, density and volume of the body to the floating force.

We know that the density of wood is equal to 750 [kg/m^3]

density = m / V

where:

m = mass = 165[kg]

V = volume [m^3]

V = m / density

V = 165 / 750

V = 0.22 [m^3]

The floating force is equal to:

F = density * g * V

F = 750*9.81*0.22

F = 1618.65[N]

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3 years ago
How old is a bone that has 12.5% of the original amount radioactive carbon 14 remaining?
nlexa [21]
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0.125*N₀=N₀*2^-(t/T), N₀ cancels out and we get:

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ln(0.125)=-(t/T)*ln(2), we divide by ln(2),

ln(0.125)/ln(2)=-t/T, multiply by T,

{ln(0.125)/ln(2)}*T=-t, divide by (-1) and plug in T=5730 years,

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3 years ago
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Answer:

v = 27.456 m/s

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The support pressure needed of the water in the straw can be calculated by the formula

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This pressure is compensated by 0.5*r*v^2 of the air,

Hence,

0.5*1.3*v^2 = 490

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8 0
3 years ago
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By the law of momentum conservation:-
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5 0
3 years ago
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