1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slega [8]
3 years ago
9

If a seismic wave has a period of 0.0202s, find the frequency of the wave.

Physics
1 answer:
maw [93]3 years ago
7 0

Answer:

49.5 Hz.

Explanation:

From the question given above, the following data were obtained:

Period (T) = 0.0202 s

Frequency (f) =?

The frequency and period of a wave are related according to the following equation:

Frequency (f) = 1 / period (T)

f = 1/T

With the above formula, we can obtain the frequency of the wave as follow:

Period (T) = 0.0202 s

Frequency (f) =?

f = 1/T

f = 1/0.0202

f = 49.5 Hz

Therefore the frequency of the wave is 49.5 Hz.

You might be interested in
the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled p
atroni [7]

Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.

The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.

Learn more about acceleration here: brainly.com/question/933224

Learn more: brainly.com/question/25887663

3 0
2 years ago
In Converging and Diverging lenses all real images are
AlladinOne [14]
B.......................
5 0
3 years ago
Read 2 more answers
An object of mass m is hung from a spring and set into oscillation. The period of the oscillation is measured and recorded as T.
sergejj [24]

Answer:\sqrt{2}T

Explanation:

Given

object of mass m is suspended from spring and set in oscillation with time Period T

We know Time period of a mass in oscillation is given by

T=2\pi \sqrt{\frac{m}{k}}

where k=spring constant

When mass m is replaced by a mass of 2 m time period is given by

T'=2\pi \sqrt{\frac{2m}{k}}

T'=\sqrt{2}\times 2\pi \sqrt{\frac{m}{k}}

T'=\sqrt{2}T

i.e. New time period becomes \sqrt{2} times of previous one

                         

7 0
2 years ago
An RV is traveling 60 km/h along a highway. A boy sitting near the driver of the RV throws a ball to another boy at the back end
alina1380 [7]

Answer:

Speed of the ball relative to the boys: 25 km/h

Speed of the ball relative to a stationary observer: 35 km/h

Explanation:

The RV is travelling at a velocity of

v_{RV}=+60 km/h

Here we have taken the direction of motion of the RV as positive direction.

The boy sitting near the driver throws the ball back with speed of 25 km/h, so the velocity of the ball in the reference frame of the RV is

v_B = -25 km/h

with negative sign since it is travelling in the opposite direction relative to the RV. Therefore, this is the velocity measured by every observer in the reference frame of the RV: so the speed measured by the boys is

v = 25 km/h

Instead, a stationary observer outside the RV measures a velocity of the ball given by the algebraic sum of the two velocities:

v = +60 km/h + (-25 km/h) = +35 km/h

So, he/she measures a speed of 35 km/h.

5 0
3 years ago
An electron is released from rest in a weak electric field given by E =-2.30 x 10-10 N/Cj. After the electron has traveled a ver
Goshia [24]

Explanation:

It is given that,

An electron is released from rest in a weak electric field of, E=2.3\times 10^{-10}\ N/C

Vertical distance covered, s=1\ \mu m=10^{-6}\ m

We need to find the speed of the electron. Let its speed is v. Using third equation of motion as :

v^2-u^2=2as

v^2=2as.............(1)

Electric force is F_e and force of gravity is F_g. As both forces are acting in downward direction. So, total force is:

F=mg+qE

F=9.1\times 10^{-31}\times 9.8+1.6\times 10^{-19}\times 2.3\times 10^{-10}

F=4.57\times 10^{-29}\ N

Acceleration of the electron, a=\dfrac{F}{m}

a=\dfrac{4.57\times 10^{-29}\ N}{9.1\times 10^{-31}\ kg}

a=50.21\ m/s^2

Put the value of a in equation (1) as :

v=\sqrt{2as}

v=\sqrt{2\times 50.21\times 10^{-6}}

v = 0.010 m/s

So, the speed of the electron is 0.010 m/s. Hence, this is the required solution.

6 0
3 years ago
Other questions:
  • A tuning fork vibrates 88 times in 0.20 s what is its frequency
    15·1 answer
  • The study of the living and non living things in a environment is
    9·1 answer
  • A positive test charge q is released from rest at distance r away from a charge of Q and a distance 2r away from a charge of 2Q.
    8·1 answer
  • Two objects of different mass rest on earth. Which one experiences the greater acceleration due to gravity?
    10·1 answer
  • You and I see, hear, and think with ___________________________. Waves carry _____________________. The wave in the speaker, on
    6·1 answer
  • the acceleration due to gravity on the moon is 1.6 m/s^2 what is the gravitational potential energy of a 1200 kg lander resting
    6·1 answer
  • A 56.0 kg bungee jumper jumps off a bridge and undergoes simple harmonic motion. If the period of oscillation is 11.2 s, what is
    12·1 answer
  • Vary the sled’s height and mass. Observe the effect of each change on the potential energy of the sled.
    6·1 answer
  • Input Voltage = 220V
    12·1 answer
  • Microscopes are used to study the structures of rocks. Over time, microscopes have become more and more powerful.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!