Answer:
D) directly, inversely
Explanation:
The energy of a photon of light is directly proportional to its frequency and inversely proportional to its wavelength.
Frequency is the number of waves that passes through a point per unit of time.
Wavelength is the is the distance between successive crests or troughs on a wave.
Mathematically, frequency is related to wavelength and velocity using;
Energy = h x f
where h is the Planck's constant
f is the frequency
Since c = f ∧
where f is the frequency of the wave
∧ is the wavelength of the wave
c is the speed of light
So;
f = c/∧
Therefore;
E = 
From the equation, we see an inverse relationship between E and wavelength and a direct one with frequency.
Answer:
pahingi po ng pic pls para masagutang kopo iyan
To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2<span>°</span>)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.
Multiply these numbers and there’s your answer
To solve this problem, we use the formula
λ = s sin θ
where s is the separation and θ is the angle interference
So,
λ = 20 x 10^-6 sin 2.5
λ = 8.72 x 10^-7 m
The required angle for the fourth order bright fringe is
θb = sin⁻¹ (4λ / s) = sin⁻¹ (4 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 10.04°
The required angle for the fourth order dark fringe is
θd = sin⁻¹ (4.5 λ / s) = sin⁻¹ (4.5 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 11.31°
