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tresset_1 [31]
3 years ago
9

What two quantities do you have to know to calculate the density of and object?

Physics
1 answer:
charle [14.2K]3 years ago
3 0
'Density' is defined as (mass) / (volume). You need enough information to be able to measure or calculate the mass and the volume of the object.
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An experiment is designed to investigate the relation between the pressure and temperature in a tank that has a constant volume
viva [34]

Answer:

3rd order polynomial

Explanation:

Given that the increase in the order of the polynomial the error between the curve fit and measured data will decreases hence  :

The polynomial order that is best to use is the 3rd order polynomial, this is because using a 3rd order polynomial will produce a less variance and a low Bias

4 0
3 years ago
Why is the overall charge of the atom neutral or zero?
MrRissso [65]

Answer:

B

Explanation:

this is because the neutrons do not have a charge, the things that have charge in an atom are electrons and protons.

and in the nucleus of an atom, there are protons and neutrons so you can see that A is not the answer

if you see the periodic table, you will know that the number of electrons and protons are equal, so the charges cancel each other out, hence the charge of an atom will be neutral

let me give you a tip which I got from my teacher, never write there is no charge in the atom, this suggests that there is no protons or electrons.

instead, write, the it is neutral

hope it helps if not please report it so that someone else gets to try it out

7 0
3 years ago
The once-ler used what to make thneeds
Bogdan [553]
He used truffula trees to make thneeds
6 0
3 years ago
If the action force is a player kicking a soccer ball, then what is the reaction force?
LiRa [457]
The force acting on his feet.
4 0
3 years ago
A Carnot air conditioner operates between an indoor temperature of 20°C and an outdoor temperature of 39°C. How much energy does
Gelneren [198K]

Answer:

D. 130 J

Explanation:

The coefficient of performance for a machine that is being used to cool, is given by:

COP=\frac{Q_C}{W}=\frac{T_C}{T_H-T_C}

Here Q_C  is the heat removed from the cold reservoir, W is the work required, that is, the energy required to remove the heat from the interior of the house, T_C is the cold temperature and T_H is the hot temperature. Recall use absolutes temperatures(273.15+^\circ C). Replacing and solving for W:

W=Q_c\frac{T_H-T_C}{T_C}\\W=2000J\frac{312.15K-293.15K}{293.15K}\\W=129.63J

8 0
3 years ago
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