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goldfiish [28.3K]
3 years ago
13

A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the

average force on ball by the golf club?
Physics
1 answer:
Liula [17]3 years ago
4 0

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, \Delta t=0.003\ s

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N

So, the average force on ball by the golf club is 340 N.

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At the center of a 50 m diameter circular ice rink, if a 77 kg skater traveling at 2.3 m/s and then collides with a 63 kg skates traveling at 3.7 m/s. This is how long it will take them to glide to the edge of the rink:

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For them to be able to get to the edge which is 50 m away it will take them 23.9 seconds.

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tresset_1 [31]

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Explanation: To find the answer, we need to know more about the Orbital and escape velocities.

<h3>What is Orbital and Escape velocity?</h3>
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                   V_o=\sqrt{gR}

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Learn more about orbital and escape velocity here:

brainly.com/question/28045208

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valina [46]

Answer:

Explanation:

From the given information:

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