Answer:
Work is the energy transferred to or from an object via the application of force along a displacement.
Answer:
Explanation:
<u>1. Name of the variables:</u>
![f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration](https://tex.z-dn.net/?f=f%3Afrequency%5C%5C%5C%5C%20%5Comega%3Aangular%5Ctext%7B%20%7Dspeed%5C%5C%5C%5C%20a_c%3Acentripetal%5Ctext%7B%20%7Dacceleration%5C%5C%5C%5C%20F_c%3Acentripetal%5Ctext%7B%20%7Dforce%5C%5C%20%5C%5C%20m%3Amass%5C%5C%20%5C%5C%20d%3Adiameter%5C%5C%20%5C%5C%20r%3Aradius%5C%5C%20%5C%5C%20g%3Agravitational%5Ctext%7B%20%7Dacceleration)
<u>2. Formulae:</u>
![f=\dfrac{number\text{ }of\text{ }revolutions}{time}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7Bnumber%5Ctext%7B%20%7Dof%5Ctext%7B%20%7Drevolutions%7D%7Btime%7D)
![\omega=2\pi f](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%20f)
![a_c=\omega^2 r](https://tex.z-dn.net/?f=a_c%3D%5Comega%5E2%20r)
![F_c=m\times a_c](https://tex.z-dn.net/?f=F_c%3Dm%5Ctimes%20a_c)
<u>3. Solution (calculations)</u>
![f=\dfrac{1}{1.65s}=0.\overline{60}s^{-1}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B1%7D%7B1.65s%7D%3D0.%5Coverline%7B60%7Ds%5E%7B-1%7D)
![\omega=2\pi\times0.\overline{60}\approx 3.808rad/s](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%5Ctimes0.%5Coverline%7B60%7D%5Capprox%203.808rad%2Fs)
![a_c=(3.808rad/s)^2\times (3.74/2m)=27.12m/s^2](https://tex.z-dn.net/?f=a_c%3D%283.808rad%2Fs%29%5E2%5Ctimes%20%283.74%2F2m%29%3D27.12m%2Fs%5E2)
![F_c=45.2kg\times27.12m/s^2=1,225.67N\approx 1,230N](https://tex.z-dn.net/?f=F_c%3D45.2kg%5Ctimes27.12m%2Fs%5E2%3D1%2C225.67N%5Capprox%201%2C230N)
Answer:
the answer is B
Explanation:
speed is the rate at which the distance covered changes or the distance divided by the time taken.
scalar is always positive.
The correct answer is D. I alread took this test.