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3 years ago

Expand and simplify (2^x+5)^2

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

5 0

Answer:

\left(2^x+5\right)^2 4^x+5\cdot \:2^{1+x}+25

Step-by-step explanation:

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3 years ago

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3 years ago

You’ve been asked to order cake for your school dance. Here’s a formula for the scenario: z=xa/y

olga nikolaevna [1]

Answer:

The number of cake for order is 15 cakes .

Step-by-step explanation:

Given as :

Total number of people to attend the dance = x = 60

The number of slices each person will eat = A = 2 slices

The number of slices per cake = y = 8 slices

Let The number of cake for order = z

Now, According to question

Total slices of cake required for 60 people when each people eat 2 slices = total number of people × number of slices each person will eat

i.e Total slices of cake required for 60 people when each people eat 2 slices = x × A

Or, Total slices of cake required for 60 people when each people eat 2 slices = 60 × 2 slices

Or,Total slices of cake required for 60 people when each people eat 2 slices = 120 slices

Again

∵ number of slices per cake = 8

∴ The number of cake for order = $\dfrac{\textrm Total slices of cake required for 60 people when each people eat 2 slices}{\textrm number of slices per cake }$

Or, z = $\frac{x\times A}{y}$

i.e z = $\frac{120}{8}$

∴ z = 15 cakes

So,The number of cake for order = z = 15 cakes

Hence,The number of cake for order is 15 cakes . Answer

7 0

3 years ago

(7+4)6 = Step by step is 42+24=66

ddd [48]

Answer:

Step-by-step explanation:

Add what is in the parenthesis, in this case 7+4:

(7+4)

=11

Multiply 11 by 6:

(11)6

=66

hope this helps :)

5 0

3 years ago

Read 2 more answers

10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend

ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

=18 +16+14+12+10+8+6+4+2

= 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

=6 +4

=10

Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

=6 +4

=10

Hence proved.

3 0

3 years ago