Answer:
(c) 6.91x10^14 Hz
Explanation:
Find the level energy of n=2 and n=5, using the formula:

where 


To jump from n=2 to n=5 the electron absorbs a photon with energy equal to
, using the next formula to find specific wavelength
to that energy

Where
is the speed of light (
) and
is Planck's constant (
). Solve for
:

The frequency of this wavelength is calculated with this formula:


Answer:
Ví dụ 1 : Hai vật xuất phát từ A và B cách nhau 400m chuyển động cùng chiều theo hướng từ A đến B. Vật thứ nhất chuyển động đều từ A với vận tốc 36km/h. Vật thứ hai chuyển động đều từ B với vận tốc 18km/h. Sau bao lâu hai vật gặp nhau ? Gặp nhau chỗ nào
<h3><u>Answer;</u></h3>
travel through solids
P waves and S waves are alike in that they<u> both travel through solids</u>.
<h3><u>Explanation;</u></h3>
- <em><u>P-waves and S-waves are types of seismic waves.</u></em> These waves are produced during an earthquake, that transmit energy released around the earth.
- <u><em>P-waves travel the fastest and also travel through solids, liquids and gases. </em></u>They are push and pull waves and thus they cause rock particles to move back and forth.
- <u><em>S-wave son the other hand arrive at a given point after the p-waves. They do not travel as fast as P-waves. They travel through solids but not in liquids and gases.</em></u> S -waves cause the rocks to move side to side.
The change in surface area of Gaussian surface with radius (r) is 8πr.
<h3>
Electric field from Coulomb's law</h3>
The electric field experienced by a charge is calculated as follows;

where;
- E is the electric field
- Q is the charge
- r is the radius
The electric field reduces by a factor of 
<h3>Surface area of a Gaussian surface;</h3>
The surface area of a sphere is given as;

<h3>Change in area with r</h3>

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.
Learn more about area of Gaussian surfaces here: brainly.com/question/17060446
Answer:
E
Explanation:
Using Coulomb's law equation
Force of the charge = k qQ /d²
and E = F/ q
substitute for F
E = ( K Qq/ d² ) / q
q cancel q
E = KQ / d²
so twice the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²