The balanced equation that shows the reaction between oxalic acid and permanganate ion in an acidic medium is: 2MnO4- + 5H2C2O4 + 6H+ -> 2Mn(2+) + 10CO2 + 8H2O. Thus, 1 mole of oxalic acid reacts with 0.4 mole of permanganate ion. This was obtained using stoichiometry:
1 mol H2C2O4 x (2 mol MnO4-/ 5 mol H2C2O4) = 0.4 mol MnO4-
In this redox reaction, the permanganate is reduced to manganese(II) ion.
Good luck with your assignment :)
Answer:
We need 0.095 moles of ethanol
Explanation:
Step 1: Data given
Number of moles water = 0.095 moles
Step 2: The balanced equation
CH3CH2OH + O2 ⇒ H2O + CH3COOH
Step 3: Calculate moles of ethanol
For 1 mol ethanol we need 1 mol oxygen to produce 1 mol water and 1 mol acetic acid
For 0.095 moles water, we need 0.095 moles ethanol and 0.095 moles oxygen
We need 0.095 moles of ethanol
Answer:
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hope this helps!
