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goblinko [34]
3 years ago
12

Write names of one diatomic and tetra -atomic element.

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
7 0
Nitrogen is diatomic which exists as N2. This is because of its small size and high electronegativity.

Phosphorus is tetra atomic which exists as P4. 
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Based on the reaction below:
Sidana [21]

N₂ + 3H₂ ⇄ 2NH₃ + heat

In the given equilibrium, we notice that the heat is on the right. which means that if the heat requirements don't meet, the reactants on the right will no longer react due to the lack of heat

but because the reactants on the left don't have such weaknesses, they will keep reacting hence producing more and more ammonia until a new equilibrium is reached

where there will be more ammonia and less nitrogen and hydrogen as compared to the equilibrium we had initially

5 0
3 years ago
Read 2 more answers
How many moles of NaCl are equivalent to 15.6<br> grams of NaCl
NeX [460]

One mole of NaCl has a mass of approximately 58.5 grams. This gives it a conversion factor of 1/58.5

Hope This Helped

4 0
4 years ago
Substance formed by the chemical combination of elements is called
nikitadnepr [17]

Answer:

chemical equation

Explanation:

3 0
3 years ago
What is the equilibrium partial pressure of water vapor above a mixture of 62.9 g H2O and 33.2 g HOCH2CH2OH at 55 °C. The partia
bija089 [108]

Answer : The partial pressure of H_2O is 102.3 mmHg.

Explanation :

As per question,

Mass of H_2O = 62.9 g

Mass of HOCH_2CH_2OH = 33.2 g

Molar mass of H_2O = 18 g/mole

Molar mass of HOCH_2CH_2OH = 62 g/mole

First we have to calculate the moles of H_2O and HOCH_2CH_2OH.

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{62.9g}{18g/mole}=3.49mole

\text{Moles of }HOCH_2CH_2OH=\frac{\text{Mass of }HOCH_2CH_2OH}{\text{Molar mass of }HOCH_2CH_2OH}=\frac{33.2g}{62g/mole}=0.536mole

Now we have to calculate the mole fraction of H_2O and HOCH_2CH_2OH.

\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }HOCH_2CH_2OH}=\frac{3.49}{3.49+0.536}=0.867

\text{Mole fraction of }HOCH_2CH_2OH=\frac{\text{Moles of }HOCH_2CH_2OH}{\text{Moles of }H_2O+\text{Moles of }HOCH_2CH_2OH}=\frac{0.536}{3.49+0.536}=0.134

Now we have to partial pressure of H_2O.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of water vapor

p_T = total pressure of gas

X = mole fraction of water vapor

p_{H_2O}=X_{H_2O}\times p_T

p_{H_2O}=0.867\times 118.0mmHg=102.3mmHg

Therefore, the partial pressure of H_2O is 102.3 mmHg.

3 0
3 years ago
Find the wavelength (in nanometers) of a yellow caution<br> lightwhose frequency is 5.4 X 1014 s-1.
MissTica

Answer:

λ = 555.55 nm

Explanation:

the photon energy equation

  • E = h*f

∴ h = 6.626 E-34 J*s.....Planck's constant

∴ f = 5.4 E14 s-1

⇒ E = (6.626 E-34 J*s)(5.4 E14 s-1) = 3.578 E-19 J

∴ E = hc/λ

⇒ λ = hc/E

∴ c ≅ 3.0 E8 m/s

⇒ λ = ((6.626 E-34 J*s)(3.0 E8 m/s))/(3.578 E-19 J)

⇒ λ = (5.555 E-7 m)×(1 E9 nm/m) = 555.55 nm

8 0
3 years ago
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