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irinina [24]
3 years ago
11

The best lewis structure for sulfuric acid has zero formal charges, sulfur as the central atom, and no bonds between s and h. ho

w many single and double bonds, respectively, are there in this lewis structure?

Chemistry
2 answers:
kherson [118]3 years ago
7 0

Explanation:

Sulfuric acid also known as H_{2}SO_{4} contains two hydrogen atoms, one sulfur atom and four oxygen atoms.

And it is given that the formal charge on a sulfuric acid molecule is zero. So, sulfur atom is bonded with two oxygen atoms through a double bond on each oxygen atom. The sulfur is also attached to another two oxygen atoms through a single bond for each oxygen atom.

Further, the each oxygen with single bond is attached to one hydrogen atom each.

Marianna [84]3 years ago
6 0

If we are to draw the sulfuric acid structure based on Lewis it would look like:

                       O

                      ll

                O = S – O –H

                       l

                      O

                       l

                       H

 

So from this, we can see that there are 2 double bonds (O = S) and 4 single bonds (S – O and O – H).

 

Therefore the answer is:

4 single, 2 double

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<span>1.40 x 10^5 kilograms of calcium oxide The reaction looks like SO2 + CaO => CaSO3 First, determine the mass of sulfur in the coal 5.00 x 10^6 * 1.60 x 10^-2 = 8.00 x 10^4 Now lookup the atomic weights of Sulfur, Calcium, and Oxygen. Sulfur = 32.065 Calcium = 40.078 Oxygen = 15.999 Calculate the molar mass of CaO CaO = 40.078 + 15.999 = 56.077 Since 1 atom of sulfur makes 1 atom of sulfur dioxide, we don't need the molar mass of sulfur dioxide. We merely need the number of moles of sulfur we're burning. divide the mass of sulfur by the atomic weight. 8.00 x 10^4 / 32.065 = 2.49 x 10^3 moles Since 1 molecule of sulfur dioxide is reacted with 1 molecule of calcium oxide, just multiply the number of moles needed by the molar mass 2.49 x 10^3 * 56.077 = 1.40 x 10^5 So you need to use 1.40 x 10^5 kilograms of calcium oxide per day to treat the sulfur dioxide generated by burning 5.00 x 10^6 kilograms of coal with 1.60% sulfur.</span>
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Are the properties of Rubidium more similar to those of cesium or those of strontium?
fenix001 [56]

More similar to Cesium

Explanation:

The properties of Rubidium are more similar to those of cesium compared to strontium.

Elements in the same group on the periodic table have similar chemical properties.

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Learn more:

Sodium brainly.com/question/6324347

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Answer:

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Explanation:

Based on the reaction:

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<em>Where 4 moles of Al reacts in excess of oxygen to produce 2 moles of aluminium oxide.</em>

<em />

To solve this question we must find the moles of Aluminium. With these moles we can find the moles of aluminium oxide using the reaction:

<em>Moles Al -Molar mass: 26.9815g/mol-</em>

6.50g * (1mol / 26.9815g) = 0.241 moles Al

<em>Mass Al₂O₃ -Molar mass: 101.96g/mol-</em>

0.241 moles Al * (2 mol Al2O3 / 4 mol Al) = 0.120 moles Al2O3

0.120 moles Al2O3 * (101.96g / mol) =

12.3g of Al2O3 are produced.

Right answer is:

<h3>d. 12.3 grams of Al2O3 </h3>

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