Question

How many grams of solute are needed to make 2.50 L of a 1.75 M solution of Ba(NO3)2?

Answer 1

1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2. Details about molarity can be found below.

How to calculate mass?

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles can be calculated by using the following formula:

Molarity = no of moles ÷ volume

no of moles = 1.75 × 2.5

no of moles = 4.38mol

molar mass of Ba(NO3)2 = 261.34g/mol

mass of Ba(NO3)2 = 261.34 × 4.38

mass of Ba(NO3)2 = 1143.4grams.

Therefore, 1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2.

Learn more about mass at: brainly.com/question/19694949