Answer and work for this problem

Chemistry

1 answer:

MArishka [77]3 years ago

6 0

We can write the balanced equation for the synthesis reaction as
H2(g) + Cl2(g) → 2HCl(g)

We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
mass of H2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol H2 / 2 mol HCl) *
(2.02 g H2 / 1 mol H2)
= 4.056 g H2

We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
(70.91 g Cl2 / 1 mol Cl2)
= 142.4 g Cl2

Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.

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In the following reaction, how many moles of CO2 will form if 10 moles of C3H4 are reacted? How many moles of O2 will also be co

umka2103 [35]

Answer:

40 moles of O₂

30 moles of CO₂

Explanation:

Given parameters:

Number of moles of C₃H₄ = 10moles

Unknown:

Number of moles of CO₂ = ?

Solution:

The number of moles helps to understand and make quantitative measurements involving chemical reactions.

We start by solving this sort of problem by ensuring that the given equation is properly balanced;

C₃H₄ + 4O₂ → 3CO₂ + 2H₂O

We can clearly see that all the atoms are conserved.

Now, we work from the known to unknown. We know the number of moles of C₃H₄ to be 10moles;

1 mole of C₃H₄ reacted with 4 moles of O₂

10 moles of C₃H₄ will react with 10 x 4 = 40moles of O₂

1 mole of C₃H₄ will produce 3 moles of CO₂

10 moles of C₃H₄ will produce 10 x 3 = 30moles of CO₂

4 0

3 years ago

Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(

kkurt [141]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)$ $\Delta H^o_{rxn}=?$