Answer: Star formation begins when the denser parts of the cloud core collapse under their own weight/gravity. These cores typically have masses around 104 solar masses in the form of gas and dust. The cores are denser than the outer cloud, so they collapse first.
Hope this helped! :))
<span>Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles. We calculate as follows:
</span>5.31×10^21 platinum atoms ( 1 mol / 6.022 x 10^23 atoms ) ( 78 grams / 1 mol ) = 0.6878 grams platinum
Some of the benefits of using measurements to find density include the following:
- It is easy and doesn't require experiments.
- The volume of both light and dense molecule can be gotten.
Some of the challenges of using measurements to find density include the following:
- Inconsistency in the grind setting
- Temperature changes not taken into account.
<h3>What is Density?</h3>
This is defined as the mass per unit volume of a substance or te degree of compactness of a substance and can be gotten with the use of measurements or experiments.
The measurement doesn't take the temperature changes into consideration which will lead to the result being most likely incorrect. It is also advantageous because less time is used thereby making it easier.
Read more about Density here brainly.com/question/406690
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Answer:
Your answer would be D, they are all non-renewable energy sources. Hope this helps!
The above question is incomplete, here is the complete question:
Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:
Answer:
The standard molar enthalpy of formation of NO is 90.25 kJ/mol.
Explanation:
To calculate the standard molar enthalpy of formation
...[3]
Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[1] - [2] = [3]
![\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7B3%7D%3D66.4%20kJ%20-%20%5B%20-114.1%20kJ%5D%20%3D%20180.5%20kJ)
According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :
=
