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mestny [16]
3 years ago
5

What is the mass of 5.31×1021 platinum atoms?

Chemistry
2 answers:
prisoha [69]3 years ago
7 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

 </span>5.31×10^21 platinum atoms ( 1 mol / 6.022 x 10^23 atoms ) ( 78 grams / 1 mol ) = 0.6878 grams platinum
Ann [662]3 years ago
7 0

Answer: 1.72 g

Explanation:

1) The atomic mass of an element is the mass of one mole of atoms.

2) One mole of atoms is 6.022×10²³ atoms (Avogadro's number).

3) The atomic mass of platinum is 195.078 grams / mole (from a periodic table)

4) Formulas:

number of moles = number of atoms / 6.022×10²³

mass in grams = number of moles × atomic mass

5) Calculations:

number of moles = 5.31×10²¹ atoms / 6.022×10²³ atoms/mole = 0.00882 moles

mass in grams = 0.08882 mol × 195.078 g/mol = 1.72 g

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A chemist adds of a sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemi
schepotkina [342]

This is a incomplete question.The complete question is:

A chemist adds 180.0 ml of a 1.77 mol/L of sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer: 50.4 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of sodium thiosulfate solution = 1.77 M

Volume of sodium thiosulfate solution = 180.0 mL = 0.1800 L

Putting values in equation 1, we get:

\text{Moles of sodium thiosulfate}={1.77}\times{0.1800}=0.319moles

Mass of sodium thiosulfate = moles\times {\text {Molar mass}}=0.319moles\times 158.11g/mol=50.4g

Thus 50.4 g of sodium thiosulfate the chemist has added to the flask.

6 0
3 years ago
The electrophilic aromatic substitution of isopropylbenzene with FeBr3, Br2 gives 1-bromo-4-isopropylbenzene. Complete the curve
jenyasd209 [6]

Answer:

See explanation below

Explanation:

When the bromine (Br₂) reacts in presence of FeBr₃ with the isopropylbenzene, the isopropylbenzene is a ring activator, therefore, it will promote the substitution in the ortho and para positions. However, as the Isopropyl is voluminic, the ortho position would have steric hindrance and hence, this product is not formed in greater proportions. Instead, the para position becomes more available to reaction, and this product is formed in majority.

The mechanism of reaction can be seen in the following picture, along with the products of the reaction

Hope this helps

4 0
3 years ago
In the uncatalyzed reaction N2O4 (g) ⇌ 2 NO2 (g) the pressure of the gases at equilibrium are PN2O4 = 0.377 atm and PNO2 = 1.56
larisa86 [58]

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

8 0
4 years ago
How does H2So4 break up to h+ &amp; hso4 - ?
Katena32 [7]
H2So4 is a strong acid and a strong electrolyte which means that when this dissociates in water, the dissociation process is complete. The first dissociation is 

H2 SO4 = H + HSO4- 

This can further release H+ and dissociate SO4- instead already
4 0
3 years ago
As you move from left to right across the periodic table, electronegativity
svet-max [94.6K]

Answer:

Electronegativity increases as you move across the periodic table from left to right.

Explanation:

5 0
3 years ago
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