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bogdanovich [222]
3 years ago
8

_______mirrors or lenses always produce smaller images.​

Physics
1 answer:
juin [17]3 years ago
5 0

Answer:

The images produced by a convex mirror are smaller than the object it reflects. The image produced by a concave lens is always virtual. The image in a convex mirror is always upright and is smaller than the object.

Explanation:

:)

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What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?
Setler [38]

Answer:

Momentum, p=7.8\times 10^{-5}\ N-m

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m

So, the momentum of the mosquito is 7.8\times 10^{-5}\ N-m.

3 0
3 years ago
When the mass of the bottle is 0.125 kg, the average maximum height of the beanbag is m. When the mass of the bottle is 0.250 kg
Jet001 [13]

Answer:

when the mass of the bottle is 0.125 kg, the average height of the beanbag is 0.35 m.

when the mass of the bottle is 0.250 kg, the average maximum height of the beanbag is 0.91m.

when the mass of the bottle is 0.375 kg, the average maximum height of the beanbag is 1.26m.

when the mass of the bottle is 0.500 kg, the average maximum height of the beanbag is 1.57m.

Explanation:

5 0
3 years ago
When a car stops, the brakes heat up because of friction. What is this an example of?
Umnica [9.8K]
Kinetic Energy would have to be the answer. Pretty sure.
6 0
3 years ago
The Venus flytrap is known for which of these behaviors?
tensa zangetsu [6.8K]
Snapping a leaf shut around an insect, I think.
8 0
2 years ago
Please. Physics is so difficult.
Softa [21]

Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: y=2\pi\sqrt{\frac{L}{g}} where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\

Evaluate the multiplication in front

1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}

Divide both sides by 6.28

0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}

Square both sides

0.100 s^2= \frac{L}{9.8 m\backslash s^2}

Multiply both sides by m/s^2  (the s^2 will cancel out)

0.984 m = L

Now now let's find the length when it's two seconds

2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}

Divide both sides by 6.28

0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}

Square both sides

0.101 s^2 = \frac{L}{9.8 m\backslash s^2}

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

0.994 m = L

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m

4 0
2 years ago
Read 2 more answers
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