Answer:
m/s
Explanation:
Assumption: bullet leaves the muzzle at a speed of V m/s
and velocity of push received by the man be v m/s
According to newton's third law to every action there is always an equal and opposite reaction.
therefore,
mass of man× velocity = mass of bullet×its velocity
⇒70×v= 10×10^-3 ×V
solving the above eqaution we get
therefore
m/s
Fist one is a cylinder
the second, i believe is a sphere
the third is a rectangular prism
and the last is the same as the first, a cylinder
Answer:
(a). The ball's centripetal acceleration is 
(b). The magnitude of the net force is 232.9 N.
Explanation:
Given that,
Mass of baseball = 144 g
Speed = 81 mph = 36.2 m/s
Distance = 81 cm
(a). We need top calculate the ball's centripetal acceleration just before it is released
Using formula of centripetal acceleration

Where, v = speed
r = radius
Put the value into the formula



(b). We need to calculate the magnitude of the net force that is acting on the ball just before it is released
Using formula of force

Put the value into the formula


Hence, (a). The ball's centripetal acceleration is 
(b). The magnitude of the net force is 232.9 N.
Answer:
The answer is C, a thermometer reads 0.1 degree higher than it should.
Answer: = . /
Explanation:
The acceleration is
= − 0
In our case, the initial velocity has minus sign.
Thus,
=
− (−0)
=
+ 0
Substituting
0 =
2
(
+
0
) −
=
2
+
0
2
−
Thus,
0
2
=
2
−
So,
0 = −
= 8.62 −
12.9
8.25 = 7.06 m/s
Answer: = . /