You got it right on the top 3
This imply that the force applied by the gravity of the earth on the person, is equal to the force applied by the person on the earth.
According to the Newton's third law, for every force there is an equal reaction force, in the case of person standing on the earth, the gravity of the earth pulls the person by the same magnitude as the force applied by the person on the earth (which is equal to the weight of the person)..
Hm pretty much that's all for alpha decay... But always after any alpha or beta decay, gamma photons are released because the daughter products end up in an excited state so they have to release energy through gamma decay
Answer:
F = 0.84 [N]
Explanation:
In order to solve this problem we must take into account Newton's second law, which tells us that the sum of all forces applied on a body must be equal to the product of the mass of the body by its acceleration.
F = m*a
where:
F = force [N]
a = acceleration = 1.4[m/s^2]
m = mass = 0.6 [kg]
F = 0.6*1.4
F = 0.84 [N]
B) 48.0 m/s
We can actually start to solve the problem from B for simplicity.
The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation
where
is the final velocity
is the initial velocity (positive since we take downward as positive direction)
is the acceleration of gravity
s = 110 m is the vertical displacement
Solving for v, we find the final velocity (and so, the speed of the rock at impact):
A) 3.67 s
Now we can find the time of flight of the rock by using the following suvat equation
where
is the final velocity at the moment of impact
is the initial velocity
is the acceleration of gravity
t is the time it takes for the rock to reach the ground
And solving for t, we find
