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weeeeeb [17]
3 years ago
10

A wire long and with mass is positioned horizontally near the earth's surface and perpendicular to a horizontal magnetic field o

f magnitude . What current I must flow through the wire in order that the wire accelerate neither upwards nor downwards
Physics
1 answer:
Ganezh [65]3 years ago
5 0

The question is incomplete. The complete question is :

A wire 0.6 m long and with mass m = 11 g is positioned horizontally near the earth's surface and perpendicular to a horizontal magnetic field of magnitude B = 0.4 T. What current I must flow through the wire in order that the wire accelerate neither upwards nor downwards? The magnetic field is directed into the page.

Solution :

Given :

Length of the wire, L = 0.6 m

Mass of the wire length, m = 11 g

                                             = 11 \times 10^{-3} kg

Magnetic field , B = 0.4 T

Know we know that :

ILB = mg

or $I=\frac{mg}{BL}$

 $I= \frac{(11 \times 10^{-3})(9.81)}{(0.4)(0.6)}$

 I=0.44963\ A

 I = 449.63 \ mA

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                         = (1/2) (1.4 kg) (22.5 m/s)²

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3 years ago
A commuter backs her car out of her garage with an acceleration of 1.40 m/s^2. (a) How long does it take her to reach a speed of
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Answer:

a) It takes her 1.43 s to reach a speed of 2.00 m/s.

b) Her deceleration is - 2.50 m/s²

Explanation:

The equation of velocity for an object that moves in a straight line with constant acceleration is as follows:

v = v0 + a · t

Where:

v = velocty.

v0 = initial velocity.

a = acceleration.

t = time.

a) Using the equation of velocity, let´s consider that the car moves in the positive direction. Then:

v = v0 + a · t

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t = 1.43 s

It takes her 1.43 s to reach a speed of 2.00 m/s

b) Let´s use again the equation of velocity, knowing that at t = 0.800 s the velocity is 0 m/s:

v = v0 + a · t

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4 years ago
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Sergeeva-Olga [200]

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\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }

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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

There should be an image that should accompanied your question, I was able to chcek it from other sources. the acceleration of the block when the scale reads 32N is <span>4.0 m/s*s</span>
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