Answer:
The moment of inertia of this sphere is .
Explanation:
It is given that,
Mass of the sphere, m = 4.8 kg
Radius of the sphere, r = 22 cm = 0.22 m
Tangential force, F = 11.2 N
The moment of inertia of the uniform sphere is given by :
So, the moment of inertia of this sphere is . Hence, this is the required solution.
initial speed of the racer is given as
after applied force the final speed is given as
now during this speed change the racer will cover total distance 185 m
so here we will use kinematics
now the force that chute will exert on the racer will be given as
B) here following is the strategy for solving it
1. first we used kinematics to find the acceleration of the car
2. then we used Newton's II law (F = ma) to find the force
Answer:
The value is
Explanation:
From the question we are told that
The diameter of the nucleus is
The charge of the proton that makes up the nucleus is
The energy to be impacted is
Generally the radius of the nucleus is mathematically represented as
=>
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Generally from the law energy conservation we have that
i.e
Here
Here is the initial kinetic energy which is mathematically represented as
Here is the initial potential energy of the proton and the value is 0 J given that the proton is moving
Also is mathematically represented as
Here
is the final potential energy which is mathematically represented as
Here is the charge on the proton with a value of
So
=>
So
=>
Here m is the mass of the moving proton with value
So
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