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11Alexandr11 [23.1K]
2 years ago
12

A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted

by the source?
Physics
1 answer:
dsp732 years ago
6 0

Answer:

Please see below as the answer is self-explanatory.

Explanation:

  • The visible range extends roughly from 400 nm (violet) to 700 nm (red).
  • Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.
  • The wavelengths in the range of 650 to 690 nm have red as the dominant color.
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Answer:

The distance of the goggle from the edge is 5.30 m

Explanation:

Given:

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let 'i' be the angle of incidence

thus,

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i = 67.75°

Now, Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

where,

r is the angle of refraction

n₁ is the refractive index of medium 1 = 1 for air

n₂ is the refractive index of medium 1 = 1.33 for water

now,

1 × sin 67.75° = 1.33 × sin(r)

or

r = 44.09°

Now,  

the distance of googles = 2.2 + d×tan(r)  = 2.2 + (3.2 × tan(44.09°) = 5.30 m

Hence, <u>the distance of the goggle from the edge is 5.30 m</u>

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