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11Alexandr11 [23.1K]
3 years ago
12

A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted

by the source?
Physics
1 answer:
dsp733 years ago
6 0

Answer:

Please see below as the answer is self-explanatory.

Explanation:

  • The visible range extends roughly from 400 nm (violet) to 700 nm (red).
  • Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.
  • The wavelengths in the range of 650 to 690 nm have red as the dominant color.
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initial velocity = 0 = v₍i₎

final velocity = ? = v₍f₎

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First we have to find the distance d, for this we use the formula,

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D = 0(12) + ½ (4)(12)²

Distance = d = 288 m

Now to find the Vf use the formula,

V₍f₎² = v₍i₎² + 2ad

V₍f₎² = (0)2 + 2(4)(288)

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IRISSAK [1]

Answer:

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