Answer:
$800,500 (nearest dollar)
Step-by-step explanation:
The given scenario can be modeled as an <u>exponential equation</u>.
<u>General form of an exponential function</u>:

where:
- a is the initial value (y-intercept)
- b is the base (growth/decay factor) in decimal form
- x is the independent variable
- y is the dependent variable
If b > 1 then it is an increasing function
If 0 < b < 1 then it is a decreasing function
The initial value (a) is the value of the investment.
Therefore, a = 1,000,000.
If the investment <u>decreases</u> by 2.2% each year, then it will be 97.8% of the previous year.
Therefore, b = 97.8% = 0.978.
Substitute these values into the formula to create a general equation for the scenario:

(where x is the time, in years).
To find the value of the investment after 10 years, substitute x = 10 into the formula:

Therefore, the value of the investment after 10 years is $800,500 (nearest dollar).
Learn more about exponential functions here:
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