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PilotLPTM [1.2K]
2 years ago
14

What is the answer to a + b + c??

Mathematics
2 answers:
strojnjashka [21]2 years ago
6 0
Yeah you can’t add them because there different variables
marissa [1.9K]2 years ago
5 0

Answer:

You can't add these because they are different variables

Step-by-step explanation:

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Select the correct answer.
kherson [118]

Answer:

d.2/6 has a repeating decimal form

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3 years ago
The number of students who enroll in a psychology course is a Poisson random variable with mean 105. The professor in charge of
EleoNora [17]

Answer:

The answer is "0.096".

Step-by-step explanation:

In this question, the X is a number of the students who enroll in a psycholog y course,  follows a Poisson distribution with mean = \lambda= 105  

\therefore P(X=x)=\frac{e^{-105} 105^{x}}{x!},(x=0,1,2,3.....)\\\\\to p(teach\  two \ sections) = P(X \geq 119)\\\\=1-P(X

8 0
2 years ago
Center at (0, 0), radius 2
Step2247 [10]

Answer:

x² + y² = 4

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius]Here r = 2, thus

x² + y² = 4

6 0
3 years ago
For each expression, use the distributive property to write an equivalent expression.
Vlada [557]

Here u go refer to the attachment below! v

8 0
2 years ago
The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F
musickatia [10]

Answer:

P(X \geq 1)=1-P(X

P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801

And replacing we got:

P(X \geq 1) = 1-0.9801 = 0.0199

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

X \sim Binom(n=2, p=0.01)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(x \geq 1)=1-P(X

And we can find the probability:

P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801

And replacing we got:

P(X \geq 1) = 1-0.9801 = 0.0199

5 0
2 years ago
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