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12345 [234]
3 years ago
12

12a2 + 4b for a = 8 & b = -6. PLease help

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0

Answer:

744

Step-by-step explanation:

12a^2 + 4b

Plug-in:

12(8)^2 + 4(-6)

12(64) + 4(-6)

768 - 24

744

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3 years ago
Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
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Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

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therefore

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2) For x=1

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\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
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