In general, sound travels faster through

1 answer:

3 0

To answer the question "What is amplitude?", first look at the context of the question. A poem is also given before the questions which discusses about sound waves. Therefore, considering the context above, amplitude is the height of the wave.

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At STP, what is the volume of 5.13 mol of nitrogen gas? Answer in units of L.

Gre4nikov [31]

Answer: $114.91L$

Explanation:

You need to know the conversion factor first in order to solve this. Any gas occupies 22.4L per mol.

$5.13mol(\frac{22.4L}{1mol})= 114.91L$ of nitrogen gas.

7 0

3 years ago

There are eight diastereomers of 1,2,3,4,5,6-hexachlorocyclohexane. One of them is drawn. Draw the other seven in the cyclohexan

Marianna [84]

Answer:

Attached below diagram of the eight diastereomers

The Isomer that reacts so slowly is DIASTEREOMER 8

Explanation:

The Isomer that reacts so slowly is DIASTEREOMER 8 in an E2 reaction and this is because no pair of chlorine and hydrogen atoms can assume the anti-periplanar orientation that is preferred in an E2 elimination

attached below is Diagram of the eight diastereomers ( screen shot from my drawing tool )

3 0

3 years ago

3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O

Ksivusya [100]

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cu: 3 moles
HNO₃: 8 moles
Cu(NO₃)₂: 3 moles
NO: 2 moles
H₂O: 4 moles

<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

$amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}$