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Nadya [2.5K]
2 years ago
9

2. Calculate the standard emf of a cell that uses the Mg/Mg+2 and Cu/Cu+2 half-cell reactions at 25ºC. Write the equation for th

e cell reaction that occurs under standard-state conditions. (10 points)
Chemistry
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:

2.71 V

Explanation:

Usually in the cell notation, the left side shows oxidation. So,  

Oxidation half reaction:

Mg_{(s)}\rightarrow Mg^{2+}_{(aq)}+2e^-    E^o_{ox}=-E^o_{red}=-(-2.37\ V)=2.37\ V

Reduction half reaction:

Cu^{2+}_{(aq)}+2e^-\rightarrow Cu_{(s)}    E^o_{red}=0.34\ V

Overall reaction:

Mg_{(s)}+Cu^{2+}_{(aq)}\rightarrow Mg^{2+}_{(aq)}+Cu_{(s)}

E^o_{cell}=E^o_{ox}+E^o_{red}= (2.37+0.34)\ V=2.71\ V

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The empirical formula of a compound is CH. At 200 degree C, 0.145 g of this compound occupies 97.2 mL at a pressure of 0.74 atm.
Vladimir [108]

Answer:

The molecular formula = C_{6}H_{6}

Explanation:

Given that:

Mass of compound, m = 0.145 g

Temperature = 200 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (200 + 273.15) K = 473.15 K

V = 97.2 mL = 0.0972 L

Pressure = 0.74 atm

Considering,  

n=\frac{m}{M}

Using ideal gas equation as:

PV=\frac{m}{M}RT

where,  

P is the pressure

V is the volume

m is the mass of the gas

M is the molar mass of the gas

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the values in the above equation as:-

0.74\times 0.0972=\frac{0.145}{M}\times 0.0821\times 473.15

M=78.31\ g/mol

The empirical formula is = CH

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 1 = 13 g/mol

Molar mass = 78.31 g/mol

So,  

Molecular mass = n × Empirical mass

78.31 = n × 13

⇒ n ≅ 6

The molecular formula = C_{6}H_{6}

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