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Nadya [2.5K]
2 years ago
9

2. Calculate the standard emf of a cell that uses the Mg/Mg+2 and Cu/Cu+2 half-cell reactions at 25ºC. Write the equation for th

e cell reaction that occurs under standard-state conditions. (10 points)
Chemistry
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:

2.71 V

Explanation:

Usually in the cell notation, the left side shows oxidation. So,  

Oxidation half reaction:

Mg_{(s)}\rightarrow Mg^{2+}_{(aq)}+2e^-    E^o_{ox}=-E^o_{red}=-(-2.37\ V)=2.37\ V

Reduction half reaction:

Cu^{2+}_{(aq)}+2e^-\rightarrow Cu_{(s)}    E^o_{red}=0.34\ V

Overall reaction:

Mg_{(s)}+Cu^{2+}_{(aq)}\rightarrow Mg^{2+}_{(aq)}+Cu_{(s)}

E^o_{cell}=E^o_{ox}+E^o_{red}= (2.37+0.34)\ V=2.71\ V

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Does the physical form of the material matter for mass-mole<br> and mole-mass calculations?
natulia [17]
Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.

Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)

How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?

Step 1: List the known quantities and plan the problem.

Known

given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown

mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.

g Sn → mol Sn → mol HF

Step 2: Solve.

75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF

Step 3: Think about your result.

The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.
4 0
2 years ago
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You're provided a 0.50 M solution of HCl. How many moles of HCl are present in 25 ml of this solution? ​
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Answer:

0.0125 moles of HCl

Explanation:

(0.50 mol/L)(0.025 L) = 0.0125 moles of HCl

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