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Hoochie [10]
3 years ago
6

2 A 3-meter-long ramp was used to lift gold into railroads for transfers. The railroads were 1 meter off the ground. What was th

e ideal mechanical advantage of the ramp?
Chemistry
1 answer:
Nataliya [291]3 years ago
6 0

Answer:

3

Explanation:

For an ideal ramp, M.A/V.R = 1 where M.A = mechanical advantage and V.R = velocity ratio.

Now, V.R = distance moved by effort, d'/distance moved by load, d = d'/d

Now, d' = 3 m and d = 1 m.

So, V.R = d'/d = 3 m/1 m = 3

From M.A/V.R = 1

M.A = V.R = 3

So, the ideal mechanical advantage of the ramp M.A = 3  

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Anode (oxidation): Cr(s) ⇒ Cr³⁺(aq) + 3 e⁻

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On the left, it is represented the anode (oxidation) and on the right, it is represented the cathode (reduction).

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To have the global reaction, we have to multiply the reduction by 3 (so the number of electrons gained and lost are the same) and add both half-reactions.

Global reaction: Cr(s) + 3 Ag⁺(aq) ⇒ Cr³⁺(aq) + 3 Ag(s)

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