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cupoosta [38]
3 years ago
10

Sodium chloride reacts with copper sulfate to produce sodium sulfate and copper chloride. mc011-1.jpg This equation represents a

synthesis reaction. decomposition reaction. single replacement reaction. double replacement reaction.
Chemistry
2 answers:
Anarel [89]3 years ago
7 0
This is a double replacement because both Copper and Sodium reacted with each other compounds , hence "double"
Alborosie3 years ago
3 0

The reaction  represented  when sodium chloride  reacts with copper sulfate to produce sodium sulfate and copper chloride  is   a <u> double  replacement  reaction.</u>


<u><em> Explanation</em></u>

<u><em> A   double replacement  reaction </em></u>  is type of chemical reaction  where two compound react and a positive  ions   and negative ions of the two  reactant  switch places  forming new  compound.

The reaction of sodium chloride + Copper  sulfate →  sodium sulfate  + copper chloride  is a double replacement reaction because;

  •    sodium  since  it  is a more  reactive metal than copper it  replaces copper  from  it's compound  which result to formation of new products( sodium sulfate and copper chloride)
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givi [52]

According to Hasselbach-Henderson equation:

pH=pK_{a}+log\frac{[A^{-}]}{[HA]}

Here, [A^{-}] is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is CH_{3}COOK and acid is CH_{3}COOH thus, Hasselbach-Henderson equation will be as follows:

pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{2}{1}=5.06

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(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

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pH=4.76+log\frac{1}{3}=4.28

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(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

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Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{5}{1}=5.45

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{1}=4.76

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(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}

Also, pK_{a}=4.76

Putting the values in equation (1),

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3 years ago
How to find the Ka of an acid?
bonufazy [111]
We know that acids have a pH of under 7. 

We also need to:
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Answer:

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In BH2-, the central atom is boron. There is a lone pair on boron. Owing to the lone pair on boron, the molecular geometry of BH2 is bent.

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