In this question, you are given the wine/alcohol concentration (12%) and the volume of the alcohol(0.75l). You are asked the alcohol content in milli liters, so don't forget to change the unit. Then the equation would be:
Alcohol content= alcohol concentration * bottle volume
Alcohol content = 12%* 0.75l * 1000ml/l= 90ml
Explanation:
When the reaction takes place,2 grams of carbon dioxide will be made but vaporized into air.
111.1 mL of water
Explanation:
Weight per volume concentration (w/v %) is defined as
weight per volume concentration = (mass of solute (g) / volume of solution (mL)) × 100
volume of solution = (mass of solute × 100) / weight per volume concentration
volume of solution = (1 × 100) / 0.9 = 111.1 mL
volume of water = volume of solution = 111.1 mL
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weight per volume concentration
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Answer:
0.5
Explanation:
1 mole of ammonium nitrate contains 2 moles of nirogen
1 mole of nitrogen converts to 0.5 moles of ammonium nitrate
the conversation factor is 0.5
I think The answer is 34.5l
