Answer:
<u>The lengths of side A is 22.4 and B is 11.9</u>.
Step-by-step explanation:
Given:
If side A is twice as long as B and C is 25 using the Pythagorean Theorem.
Now, to find the lengths of side A and B.
Let the side B be 
So, the side A be 
Side C = 25.
Now, to solve by using Pythagorean Theorem:
A² + B² = C²



<em>Dividing both sides by 5 we get:</em>

<em>Using square root on both sides we get:</em>

<u>B rounding to the nearest tenth = 11.9.</u>
Now, to get A by substituting the value of
:

<u>A rounding to the nearest tenth = 22.4.</u>
Therefore, the lengths of side A is 22.4 and B is 11.9.
8x-6y=-96 add to this -4 times the second equation...
-8x-12y=-48
___________
-18y=-144
y=8, this makes 8x-6y=-96 become:
8x-48=-96
8x=-48
x=-6
so the solution to the system of equations is the point:
(-6,8)
Answer:
= 9x^15/7
Step-by-step explanation:
Hi there!
We can use right-triangle trigonometry to solve.
We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.
cosθ = Adjacent/Hypotenuse
We can plug in what is given:
cos(28) = A/17
Solve for 'A':
17cos(28) = <u>15.01 ft</u>
Answer: yards and meters
Step-by-step explanation: