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Katen [24]
11 months ago
8

Which reaction is mainly responsible for the cause of energy radiation from the sun?​

Physics
1 answer:
DENIUS [597]11 months ago
8 0

Nuclear fusion reaction is mainly responsible for the cause of energy radiation from the sun.

Solar energy is created due to this nuclear fusion. The discharge of energy in the sun is 10²⁶ joules per second

There is nuclear fusion of hydrogen into helium molecules.

Takes place in solar nucleus.

The type of fusion in nuclear fusion is proton-proton fusion. The 2 condition which help H-H atoms come together is large mass of the sun and the force of gravity

To know more about nuclear fusion,

brainly.com/question/14019172

#SPJ4

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A less than youthful 82.6 kg physics professor decides to run the 26.2 mile (42.195 km) Los Angeles Marathon. During his months
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A jet accelerates at a=3.92 m/s2 from rest until it reaches its takeoff velocity of 360 km/hr. It has to travel for 5 seconds at
Art [367]

Answer:

\Delta s = 1775.510\,m

Explanation:

The minimum distance for takeoff is:

\Delta s = \Delta s_{1} + \Delta s_{2}

\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a} + v_{f}\cdot \Delta t

\Delta s = \frac{(100\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}}{2\cdot (3.92\,\frac{m}{s^{2}})}+(100\,\frac{m}{s} )\cdot (5\,s)

\Delta s = 1775.510\,m

7 0
2 years ago
Your friend provides a solution to the following problem. Evaluate her solution. The problem: Jim (mass 50 kg) steps off a ledge
Mekhanik [1.2K]

Answer:

No its wrong

Correct compression is 0.41

Explanation:

After jumping from 2m height on spring attached platform platform is compressed a distance x(let).

So work done by gravity on Jim is converted into spring potential energy.

k=8000 N/m

mass of Jim =50 kg

\frac{1}{2}k(x)^{2} =m*g(2+x)

\frac{1}{2}8000(x)^{2} =50*9.8(2+x)

8.16x^{2} =2 +x

Solve this quadratic one solution is positive and other is negative.

positive one is our answer = 0.41 m

5 0
3 years ago
10. A wheelbarrow is a second-class lever. Its wheel is the fulcrum, and its
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A tension force of 175 N inclined at 20.0° above the horizontal is used to pull a 40.0 - kg packing crate a distance of 6.00 m o
Murljashka [212]

Answer:

(a) Work done by the tension force is 987 J

(b) Coefficient of kinetic friction between the crate and surface is 0.495

Explanation:

(a)

Work done by any force F in moving an object by a distance d making an angle \Theta with the direction of force  is given by

W=Fd\cos (\Theta )

W=175 \times 6 \times  \cos (20 )J=987J

Thus work done by the tension force is 987 J

(b)

Normal force on the crate is given by

N= mg-F\sin \Theta  =(40\times 9.8-175\times \sin 20)Newton

=>N=332 Newtons

Since crate is moving with constant speed . Therefore using Newtons second law .

Fcos(\Theta ) -\mu_k N=0

Where \mu_k=coefficient of kinetic friction

\therefore \mu_k=\frac{F\cos (\Theta )}{N}

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=>\mu _k= 0.495

Thus coefficient of kinetic friction between the crate and surface is 0.495

4 0
3 years ago
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