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marysya [2.9K]
3 years ago
10

Jenny wanted to test whether worms prefer light or darkness best. After

Physics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

True

Explanation:

An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. You are changing light or dark

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Why do objects move at constant speed
kati45 [8]
Most objects move at a constant speed because of friction and acceleration. The constant speed keeps them in place, and keeps a balance. 
7 0
3 years ago
An object is hung from a spring balance attached to the ceiling of an elevator cab. The balance reads 65 N when the cab is stand
lana66690 [7]

Answer:

(A) Reading will be 65 N

(B) Net force on the elevator will be 49.076 N    

Explanation:

We have given the balance force = 65 N

Acceleration due to gravity g=9.8m/sec^2

We know that W=mg

So 65=m\times 9.8

m = 6.632 kg

(a) In first case as the as the speed is constant so the force on the elevator will be 65 N

(B) In second case as the elevator is decelerating at a rate of 2.4m/sec^2

So net acceleration = 9.8-2.4=7.4m/sec^2

So net force on elevator will be = m× net acceleration = 6.632×7.4 = 49.076 N

7 0
3 years ago
12. Where is the Moon? If you see it, describe its location and appearance. ​
garri49 [273]
Do you mean in general or in a piece of paper?
3 0
3 years ago
A square plate of side 9 m is submerged in water at an incline of 60∘ with the horizontal. Its top edge is located at the surfac
Tpy6a [65]

Answer:

The force on one side of  the plate is 3093529.3 N.

Explanation:

Given that,

Side of square plate = 9 m

Angle = 60°

Water weight density = 9800 N/m³

Length of small strip is

y=\dfrac{\Delta y}{\sin60}

y=\dfrac{2\Delta y}{\sqrt{3}}

The area of strip is

dA=\dfrac{9\times2\Delta y}{\sqrt{3}}

We need to calculate the force on  one side of  the plate

Using formula of pressure

P=\dfrac{dF}{dA}

dF=P\times dA

On integrating

\int{dF}=\int_{0}^{9\sin60}{\rho g\times y\times 6\sqrt{3}dy}

F=9800\times6\sqrt{3}(\dfrac{y^2}{2})_{0}^{9\sin60}

F=9800\times6\sqrt{3}\times(\dfrac{(9\sin60)^2}{2})

F=3093529.3\ N

Hence, The force on one side of  the plate is 3093529.3 N.

7 0
3 years ago
A block is pulled along a horizontal surface at a constant speed by a force (14.1i 0 j 5.1k). The direction k is perpendicular t
Pepsi [2]

Answer:

W =84.6\ Nm

Explanation:

given,

F = 14.1 i + 0 j + 5.1 k

displacement = 6 m

Assuming block is moving in x- direction

we know,

 dW = F dx

\int dW = F\int dx

W = F\int_0^6 dx

W = F[x]_0^6

W = 14.1 \times 6

W =84.6\ Nm

hence, work done by the force is equal to W =84.6\ Nm

7 0
3 years ago
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