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Aleks04 [339]
3 years ago
11

A robot is on the surface of Mars. The angle of depression from a camera in the robot to a rock on the surface of Mars is 13.69

degrees13.69°. The camera is 198.0198.0 cm above the surface. How far is the camera from the​ rock?
Physics
1 answer:
ra1l [238]3 years ago
3 0

Answer:

The distance between the camera and the rock is 836.6 cm

Explanation:

A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:

cos α = adjacent/hypotenuse

cos(76.31) = 198.0/h

h = 198.0/cos(76.31)

h = 836.6 cm

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A spring stretches by 18 cm when a bag of potatoes weighing 56 N is suspended from its end. How much elastic potential energy in
Cerrena [4.2K]

Answer:

Elastic potential energy = 5.04 J

Explanation:

Given that

Extension e = 18 cm = 0.18 m

Force F = 56N

Elastic potential energy = 1/2Fe

Elastic Potential energy = 1/2 ×56×0.18

Elastic potential energy = 5.04 J

5 0
3 years ago
Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)
vaieri [72.5K]

Answer:

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A =  0.29 J

\mu =3716.35 J/mole

Explanation:

given data:

Kr  atomic number = 36

degree of freedom = 3

1) internal energy E = \frac{f}{2} n R T

                                = \frac{3}{2} *1*8.314*298 = 3716.35 j

2) cv = \frac{E}{T}

         = \frac{3716.35}{298} = 12.47 J/K

3) S = cv =\frac{E}{T} = 12.47 J/K

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5)chemcial potential \mu = \frac{energy}{mole} = 3716.35 J/mole

6 0
3 years ago
After a projectile is fired into the air, what is the magnitude of the acceleration
sergiy2304 [10]

Answer: Option A;  9.8 m/s^2

Explanation:

When an object is in the air, and there is no air resistance acting on the object, the only force that will act on the object is the gravitational force (on the vertical axis).

Then, if the only force acting on the object is the gravitational force, the acceleration of the object will be equal to the gravitational acceleration.

We know that the gravitational acceleration is equal to:

g = 9.8m/s^2

Then the acceleration on the vertical axis will be equal to:

a(t) = 9.8m/s^2

The correct option is the first one:

A. 9.8 m/s^2

7 0
3 years ago
How does the kinetic energy from the forward motion of a car traveling at 16 m/s
elena55 [62]

The kinetic energy in the first case is 4 times more than the second case.

Hence, option D)It is 4 times greater is the correct answer.

<h3>What is Kinetic Energy?</h3>

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given that;

  • For the first case, velocity v = 16m/s
  • For the second case, velocity = 8m/s
  • Let the mass of the car be m

For the first case, kinetic energy of the car will be;

K = (1/2)mv²

K = (1/2) × m × (16m/s)²

K = (1/2) × m × 256m²/s²

K = mass × 128m²/s²

For the second case, kinetic energy of the car will be;

K = (1/2)mv²

K = (1/2) × m × (8m/s)²

K = (1/2) × m × 64m²/s²

K = mass × 32m²/s²

Comparing the kinetic energy of the car with the same mass but different velocity, we can see that the kinetic energy in the first case is 4 times more than the second case.

Hence, option D)It is 4 times greater is the correct answer.

Learn more about kinetic energy here: brainly.com/question/12669551

#SPJ1

7 0
1 year ago
A projectile is launched from the ground with an initial velocity of 12ms at an angle of 30° above the horizontal. The projectil
netineya [11]

vi^{2}sin2thita/g =12^{2}sin2[30]/9.8=12.7Answer:

Explanation:

range is given as

6 0
3 years ago
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