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Aleks04 [339]
3 years ago
11

A robot is on the surface of Mars. The angle of depression from a camera in the robot to a rock on the surface of Mars is 13.69

degrees13.69°. The camera is 198.0198.0 cm above the surface. How far is the camera from the​ rock?
Physics
1 answer:
ra1l [238]3 years ago
3 0

Answer:

The distance between the camera and the rock is 836.6 cm

Explanation:

A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:

cos α = adjacent/hypotenuse

cos(76.31) = 198.0/h

h = 198.0/cos(76.31)

h = 836.6 cm

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43200c

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3 years ago
A 460 W heating unit is designed to operate with an applied potential difference of 120 V (a) By what percentage will its heat o
dybincka [34]

Answer:

(a) = -0.16%

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Explanation:

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we know p = \frac{v^2}{R} .....................(i)

we need to find change in power

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from equations we get

\frac{\Delta P}{P} =  \frac{2 \Delta V}{V}

\frac{\Delta P}{P} = 2 \frac{110 -120}{120}

\frac{\Delta P}{P} =  -2(\frac{10}{120})

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(b)

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7 0
3 years ago
A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C. How much water freezes onto the ice? The specific heat of
vladimir2022 [97]

For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice?  is mathematically given as

x = 9.93 g

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Where

Energy received = energy given out

Generally, the amount of water is mathematically given as

(53)(0.5)(30) = (80)(x)

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4 0
2 years ago
An ice skater starts with a velocity of 2.25 m/s in a 50.0 direction. after 8.33 m/s in a 120 direction. what is the y-component
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The y-component of the acceleration is given by:

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u_y is the y-component of the initial velocity

t is the time elapsed

For the ice skater in this problem, we have:

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user100 [1]
Answer is b) I think
3 0
3 years ago
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