Answer:
Constant volcanic eruption
Explanation:
Specif gravity = density of the material / density of water
density of the material = specific gravity * density of water
density of gold = 19.3 * 1 g/mL = 19.3 g/mL
density = mass / volume ==> Volume = mass / density
Volume = 0.4 kg * 1000 g/kg / 19.3 g/mL = 20.725 mL
Length of one side of the cube =
![\sqrt[3]{20.725 {cm}^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B20.725%20%7Bcm%7D%5E%7B3%7D%20%7D%20)
= 2.75 cm
Pass cm to inches
2.75 cm * 1 inch / 2.54 cm = 1.08 inch
Answer:
280 g Al₂O₃
Explanation:
To find the mass, you need to multiply the given value by the molar mass. This will cause the conversion because the molar mass exists as a ratio; technically, the ratio states that there are 101.96 grams per every 1 mole Al₂O₃. It is important to arrange the ratio in a way that allows for the cancellation of units. In this case, the desired unit (grams) should be in the numerator. The final answer should have 2 sig figs to reflect the given value (2.7 mol).
Molar Mass (Al₂O₃): 101.96 g/mol
2.7 moles Al₂O₃ 101.96 g
------------------------ x ------------------- = 275 g Al₂O₃ = 280 g Al₂O₃
1 mole
Answer:
Please, see attached two figures:
- The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.
- The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.
Explanation:
The red arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>
From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.
Assuming density 1.0 g/mol for water, 10 mL of water is:
Thus, the solutibily is:
