Answer: n= 0.045 mol
Explanation: amount of substance in moles is n= cV= 0.30 mol/l· 0.150 l
Answer:
The answer to your question is V2 = 1.3 l
Explanation:
Data
Pressure 1 = P1 = 1.5 atm
Volume 1 = V1 = 2.50 l
Temperature 1 = T1 = 22°C
Pressure 2 = P2 = 3 atm
Volume 2 = V2 = ?
Temperature 2 = T2 = 35°C
Process
1.- Convert temperature to °K
T1 = 22 + 273 = 295°K
T2 = 35 + 273 = 308°K
2.- Use the combine gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
3.- Substitution
V2 = (1.5 x 2.5 x 308) / (295 x 3)
4.- Simplification
V2 = 1155 / 885
5.- Result
V2 = 1.3 l
Answer:
0.0922 M
Explanation:
The problem first states that the titration is made using NaOH, and later asks about the addition of KOH. I'm going to assume NaOH was used throughout the whole problem. The result does not change if it was KOH instead.
The reaction that takes place is:
- HClO₄ + NaOH → NaClO₄ + H₂O
First we <u>calculate how many HClO₄ moles are there in the sample</u>, using the <em>given molarity and volume</em>:
- 0.624 M * 13.0 mL = 8.11 mmol HClO₄
Then we <u>calculate how many NaOH moles were added</u>:
- 0.258 M * 15.0 mL = 3.87 mmol NaOH
Now we calculate how many HClO₄ remained after the reaction:
- 8.11 - 3.87 = 4.24 mmol HClO₄
As <em>HClO₄ is a strong acid</em>, 4.24 mmol HClO₄ = 4.24 mmol H⁺
Finally we <u>calculate the molarity of H⁺</u>, using the<em> calculated number of moles and final volume</em>:
- Final volume = 31.0 mL + 15.0 mL = 46.0 mL
- 4.24 mmol / 46.0 mL = 0.0922 M
Answer:
International Union of Pure and Applied Chemistry (IUPAC) justified ways how to name organic compounds [ hydrocarbons ].
Oxygen has only a molecular name which is <u> </u><u>dioxide</u><u> </u>
