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Nat2105 [25]
2 years ago
9

What is the molarity of a solution that has 2.52 grams of NaCO3 dissolved to

Chemistry
1 answer:
sammy [17]2 years ago
5 0

Answer:

Explanation:

2.52g/ 0.125L= 20.16M

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The number of atoms present in 2.5 mole of triatomic gas is equivalent to ​
RUDIKE [14]

Answer: 1.41725 X 10^{24} atoms

Explanation:

One male of any gas containing no. of atoms$=6.023\times10^{23}$

2.5 moles of gas containing no. of atoms$=2.5\times6.023\times10^{23}$$=15.0575\times10^{23}$

The given gas is triatomic gas. Hence

No. of atoms$=3\times15.075\times10^{23}$

$=14.1725\times10^{23}$\\$=1.41725\times10^{24}$

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3 years ago
What do repeated trials in an experiment allow a scientist to do?
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Answer:

Learn from their experiment and know the possible results from trial and error

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3 years ago
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Erosion

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2 years ago
A teaspoon of powdered caffeine can be as deadly as a teaspoon of ricin. <br><br> True or False
Darina [25.2K]

A teaspoon of caffeine is <em>NOT</em> deadly as teaspoon of ricin                                                                                                            

4 0
3 years ago
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A student is adding DI water to a volumetric flask to make a 50% solution. Unfortunately, he was not paying attention and filled
dalvyx [7]

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = $\frac{m}{50}$     \left(\frac{\text{mass}}{\text{volume}}\right)

Now after adding extra 10 mL , the density becomes $\frac{m}{60}$.

Therefore, $\frac{m}{50}>\frac{m}{60}$

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3 years ago
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