Let's assume
length of rectangle is L
width of rectangle is W
the width of a rectangle is 3 meters more than one-fourth its length
so,

the perimeter is 10 meters more than twice its length
we know that
perimeter =2(L+W)
so, we get

now, we can simplify it

subtract both sides by 2L



now, we can find L

subtract both sides 3


multiply both sides by 4


so,
length of rectangle is 8 meter
width of rectangle is 5 meter ............Answer
Answer:
you didn't show the following
Step-by-step explanation:
but I'd love to help

solve for "w" to get the width
what's the area of a rectangle? length * width, or lw
Step-by-step explanation:
3n-5=(-8*6)+(-8*5n) distributive property
3n-5=-48-40n
3n+40n=-48+5 add property
43n=-43 add property
43n/43=-43/43 division property
n=-1
Hope this helps, although, if you don't understand something, tell me!