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Viktor [21]
3 years ago
11

The amount that results when $4,000 is compounded at 6% annually over seven years.

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:$ 6,014.52

Step-by-step explanation:

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Please answer this multiple choice question, will give brainliest!
solmaris [256]

Answer:

C.

Step-by-step explanation:

<D and <A are vertical angles.

Vertical angles are congruent.

Congruent means the same or equal.

7 0
3 years ago
An unbiased coin is tossed 15 times. In how many ways can the coin land tails either exactly 8 times orexactly 5 times?
Kitty [74]

Answer:

Probability to get tails exactly 8 times or exactly 5 times is 0.29

Step-by-step explanation:

No of ways the coins lands tails exactly 8 times

P(8) = 15C8 × 0.5^{8} × 0.5^{15-8}

No of ways the coin lands tails exactly 5 times

P(5) = 15C5 × 0.5^{5} × 0.5^{15-5}

Probability to get tails exactly 8 times or 5 times

P(8)+P(5) =  15C8 × 0.5^{15} + 15C5 × 0.5^{15}

P = 0.5^{15} (  15C8 + 15C5 )

P = 0.5^{15} ( (  \frac{15!}{8!(15-8)!}  ) + ( \frac{15!}{5!(15-5)!} ) )

P = 0.5^{15} ( 6435 + 3003 )

P = 0.5^{15} ( 9438)

P = 0.5^{14} ( 4719)

P =  \frac{4719}{16384}

P = 0.29

8 0
3 years ago
Please help me with this question!
pav-90 [236]

Answer:

n = 20

Step-by-step explanation:

hope this help you ! ;)))

8 0
3 years ago
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
If Q is between A and M and MQ=7.3 and AM =8.5, then QA =
aleksandrvk [35]

Simply put if Q is between A and M then you just subtract MQ from AM to to get QA

8 0
3 years ago
Read 2 more answers
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