Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
<em>Answer:</em>
<em>The answer is 18k + 22p - 10</em>
<em>Step-by-step explanation:</em>
<em>That is the right answer </em>
Hello!
Since we already see an equation that equals y (-2x-4), we can plug that equation into the first to solve for x.
x+4(-2x-4)=19
x-8x-16=19
-7x=35
x=-5
Now that we know the value of x, we will plug it into the second equation to solve for y.
y=-2(-5)-4
y=10=4
y=6
This gives us the answer belowThe correct answer is A) (-5,6)
I hope this helps!
1. 10 pages ->3 min
1 page->0.3min or 18 seconds
2. $28->6h
$28/6->1h
$4/2/3 or $14/3->1h