Given:
EFGH is a square.
To find:
The .
Solution:
We know that all interior angles of a square are right angles.
(Right angle)
The diagonals of square are always the angle bisectors.
FH is a diagonal of the square. So, it bisects the angle EHG.
Therefore, the measure of angle FHG is 45 degrees.
If this helps you please make it brainliest.
14. She has 12 possible choices.
15. $96
16. I don’t know about this one, sorry.
I7. 4/7
18. 1/3
Hope this helps!
Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed
Answer: Crickets make 172 chirps/min at 80 degrees Fahrenheit
Step-by-step explanation:
Step 1
Using the point slope formulae for Linear functions , we have that
y - y1 = m(x - x1)
where x and y are two points representing the temperature and chirps /min respectively
And
m= slope
Step 2 : Finding the slope , m
where x1=60
y1=92
x2= 75
y2=152
m= (y2-y1)/ (x2-x1)
= (152- 92)/(75-60)
=60/15 =4
Bringing down the point/slope formula and imputing the known values to find our equation to show the relationship cricket make per minute and the temperature
y - y1 = m(x - x1)
y - 92= 4(x - 60)
y - 92 = 4x -240
y = 4x - 240 + 92
y = 4x - 148
Step 3
To find the number of chirps be per minute (y) if the temperature is 80 degrees Fahrenheit( x)
y = 4(80) - 160
y = 320 - 148
y = 172 chirps/min at 80 degrees Fahrenheit
Answer:
Line does not represent direct variation.
Step-by-step explanation:
If the line goes thru the origin, it represents direct variation. Otherwise it does not.
Start by finding the slope of this line:
As we move from (-4,3) to (4,3), x increases by 8 but y does not change. Thus, the slope is 0/8, or just 0. Thus, the equation of this line is y = 3, which does NOT go thru the origin; thus, the points given do NOT represent direct variation.