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nika2105 [10]
3 years ago
5

A 3-column table with 10 rows. Column 1 is labeled Trial with entries 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. Column 2 is labeled Outcome

with entries H T, T T, H T, H H, H T, H T, T T, H T, T T, H H. Column 3 is labeled Result with entries Fail, pass, fail, fail, fail, fail, pass, fail, pass, fail.
A pop quiz has 2 True/False questions. Paris used a 10-trial coin flip to simulate the results of guessing on the quiz. If T represents answering a question correctly, what is the experimental probability of correctly answering both questions by guessing?

Frequency of observed desired outcome:
Number of trials:
Experimental probability:
This is in edgenu*ty if that helps
Mathematics
2 answers:
lara31 [8.8K]3 years ago
9 0

Answer:

Frequency of observed desired outcome: 3

Number of trials: 10

Experimental probability: 3/10

Monkey
2 years ago
Thank you so much this really helped me
Viktor [21]3 years ago
4 0

The correct answers are:

Frequency of observed desired outcome:  3

Number of trials:  10

Experimental probability:  3/10

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blondinia [14]
The rope is 1 and 1/3 long,1 is the same as saying 3/3,
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4/3 x 1/2 = 4/6 , which if simplified = 2/3, this means that each friend gets 2/3 foot of rope.

You can draw this in a diagram by drawing the 1 foot of rope, and then dividing it up into 3 sections. Then add the 1/3 foot of rope into the drawing. It should then be easy to see that altogether there are 4 separate sections of rope and that if each friend has two sections then they will be sharing equal amounts, so consequently each friend has two of the thirds of rope, 2/3

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3 years ago
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Phoenix [80]

Answer:

5y^{6}\sqrt{2}

Step-by-step explanation:

We want to  simplify:

\sqrt{50y^{12}}

We rewrite as:

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We split the radical sign to obtain:

\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}

Simplify the square root for the perfect squares to get:

5y^{6}\sqrt{2}

Therefore the simplified form is: 5y^{6}\sqrt{2}

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