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MrRissso [65]
3 years ago
6

In your own words, explain a crucial piece of evidence that Johannes Kepler could have used to support one of his laws of planet

ary motion.
Chemistry
1 answer:
lutik1710 [3]3 years ago
8 0
Johannes Kepler could have used Evidence gathered by "Tycho Brahe" <span>on the detailed positions of Mars in the sky. He used his entire data, plus Newton's view of observation, then he formulated his law of Planetary motion

Hope this helps!</span>
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Issues guidelines for financial system operated by all commerical banks in India​
timurjin [86]
What exactly are you asking
4 0
3 years ago
Melatonin has the chemical formula C13H16N2O2. Less than 10 milligrams(0.01g) Convert the melatonin to moles
oee [108]

Answer: There are 0.000043 moles of melatonin.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

given mass = 10 mg = 0.01 g

molar mass of C_{13}H_{16}N_2O_2 = 232.28 g

{\text {moles of melatonin}}=\frac{0.01g}{232.28g/mol}=0.000043moles

Thus there are 0.000043 moles of melatonin

6 0
3 years ago
A buffer consists of 0.45 M CH3COOH (acetic acid) and 0.35 M CH3COONa. The Ka of acetic acid is 1.8 x 10-5 . a) Calculate the pH
Zigmanuir [339]

Answer:

A) pH of Buffer solution = 4.59

B) pH after 5.0 ml of 2.0 M NaOH have been added to 400 ml of the original    buffer solution = 4.65

Explanation:

This  is the Henderson-Hasselbalch Equation:

 pH = pKa + log\frac{[conjugate base]}{[acid]}

to calculate the pH of the following Buffer solutions.

8 0
3 years ago
When does the electron release the greatest amount of energry as it moves from one level to another?
gayaneshka [121]
I can't see the picture, but in general, I believe it is in dropping from the first energy level above the ground state, to the ground state.
6 0
2 years ago
How many moles of neon gas are there 25.0 L of gas or 5.0°C with a pressure of 89.9 KPa?
vladimir2022 [97]
  • Volume=25L
  • Temperature=5°C
  • Pressure=89.9kPa

Now

\\ \rm\rightarrowtail PV=nRT

\\ \rm\rightarrowtail n=\dfrac{PV}{RT}

\\ \rm\rightarrowtail n=\dfrac{89.9(25)}{5R}

\\ \rm\rightarrowtail n=89.9(5)/R

\\ \rm\rightarrowtail n=449.5/R mol

8 0
2 years ago
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