Question

If the area of a square is increased by 69%, then the side of the square is increased by what percent?

Answer 1

Answer:

Percent Increase in measure of the side of a square = 30%

Step-by-step explanation:

Let the measure of the side of a square = s

Area of the square = (Side)²

                                = s²

If the area of the square is increased by 69%

Area of the new square = s² + 69% of s²

                                        = s² + 0.69s²

                                        = 1.69s²

Therefore, measure of the side of the new square = √(Area of the square)

                                                                                    = √(1.69s²)

                                                                                    = 1.3s

Measure of side of the old square = s

Therefore, increase in measure of the square = 1.3s - s

                                                                            = 0.3s

Percent increase in the measure of the side of the square

= $\frac{\text{Increase in measure}}{\text{Measure of the side of the original square}}\times 100$

= $\frac{0.3s}{s}\times 100$

= 30%