Answer:
84.2 grams
Explanation:
you have to multiply 8.42x10^18 to get the answer above
Answer: 26.54 grams
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and 
is the excess reagent
According to stoichiometry :
As 1 moles of give = 3 moles of 
Thus 0.369 moles of 
give =
of
Mass of 
Thus 26.54 g of will be produced from the given mass.
There are two big advantages of using molarity to express concentration. The first advantage is that it's easy and convenient to use because the solute may be measured in grams, converted into moles, and mixed with a volume.
The second advantage is that the sum of the molar concentrations is the total molar concentration. This permits calculations of density and ionic strength
Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
