It means that 22.5×10^5 J of heat is required to change 1 kg of water into steam.
Latent heat of vaporization is amount of energy required to change 1 gram (in this example 1 kilogram) of material from the liquid to the gaseous state at its boiling point.
Boiling point of the water is 100°C.
Joule (J) is the standard unit for energy (in this example heat).
Evaporization is phase change process in which the water changes from a liquid to a gas (water vapor). Fore example, solar radiation can be the source of energy for evaporation.
More about heat of vaporization: brainly.com/question/14679329
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Answer:
Density is 6.16g/L
Explanation:
<em>... at exactly -15°C and exactly 1atm...</em>
<em />
Using general gas law:
PV = nRT
We can find density (Ratio of mass and volume) in an ideal gas as follows:
P/RT = n/V
<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>
n*MW = m
n = m/MW
P/RT = m/V*MW
P*MW/RT = m/V
<em>Where P is pressure: 1atm;</em>
<em>MW of chlorine pentafluoride: 130.445g/mol</em>
<em>R is gas constant: 0.082atmL/molK</em>
<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>
<em />
Replacing:
P*MW/RT = m/V
1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V
6.16g/L = m/V
<h3>Density of the gas is 6.16g/L</h3>
<em> </em>
Answer:
The answer to your question is: more less
Explanation:
I suggest you these answers:
a) PCl₅ (s) ⇒ PCl₃ (s) + Cl₂ (g)
b) ZnBr₂ (aq) + Li₃CO₃ (aq) ⇒ ZnCO₃ (s) + LiBr (aq)
c) C₂H₄ + O₂ ⇒ CO₂ (g) + H₂O (l)
Do you have to balance them?
Answer:
d) 2.7 mol
Explanation:
limit reagent is H2:
∴ Mw H2 = 2.016 g/mol
∴ Mw N2 = 28.0134 g/mol
⇒ moles NH3 = (4.0 moles H2)×(2 mol NH3/3mol H2)
⇒ moles NH3 = 2.666 mol
⇒ moles NH3 ≅ 2.7 mol
Answer : The correct answer is 2.36 mol of gold
1 mole of any element have 6.022 x 10²³ number of atoms ( Avogadro's number).
So the formula relating mole and number of atoms is given as :
Plugging value in formula :
Mole of gold = 2.36 mol
