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nlexa [21]
3 years ago
14

6 boxes of 3-inch incense sticks for $22.75 is a better buy than 8 boxes for $30 and 10 boxes for $38.00

Mathematics
1 answer:
elixir [45]3 years ago
4 0
You would want to buy 8 boxes for 30$
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Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5) , / at (- 2, 2) , and X at (4, - 1) , where x >
bazaltina [42]

Answer:

Isosceles triangles have two sides with the same length, and one side that ... Similarly, if two angles of a triangle have equal measure, then the sides ... (2) Set up an equation and solve for x. ... x = 60/2 x = 30. Each base angle of triangle ABC measures 30 degrees. ... In isosceles triangle RST, angle S is the vertex angle.

Step-by-step explanation:

8 0
3 years ago
Given two points (3, 7) and (6, 8) with a line drawn through the points, calculate the slope of the line
vredina [299]

Answer:

1/3

Step-by-step explanation:

Given two points on the line, we can find the slope using

m = (y2-y1)/(x2-x1)

    = (8-7)/(6-3)

    = 1/3

3 0
3 years ago
Read 2 more answers
2x^2 -7= 74 please show all work
skad [1K]
2x^2-7=74\\
2x^2=81\\
x^2=\dfrac{81}{2}\\
x=-\sqrt{\dfrac{81}{2}} \vee x=\sqrt{\dfrac{81}{2}}\\
x=-\dfrac{9}{\sqrt2} \vee x=\dfrac{9}{\sqrt2}}\\
x=-\dfrac{9\sqrt2}{2} \vee x=\dfrac{9\sqrt2}{2}}\\
8 0
3 years ago
Which of the following are true statements about angle parking. Angle parking spots have a larger blind spaces than perpendicula
S_A_V [24]

Answer:

Angle parking is more common than perpendicular parking.

Angle parking spots have half the blind spot as compared to perpendicular parking spaces

Step-by-step explanation:

Considering the available options, the true statement about angle parking is that" Angle parking is more common than perpendicular parking." Angle parking is mostly constructed and used for public parking. It is mostly used where the parking lots are quite busy such as motels or public garages.

Therefore, in this case, the answer is that "Angle parking is more common than perpendicular parking."

Also, "Angle parking spots have half the blind spot as compared to perpendicular parking spaces."

5 0
3 years ago
If the discriminant is positive there is exactly one real solution.
Len [333]
It is in form
0=ax^2+bx+c
0=-3x^2-2x+6
a=-3
b=-2
c=6

so
x=
x=
x=
x=
x=
x=
x= or 
7 0
3 years ago
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