Answer:
B. 8.0m/s
Explanation:
Distance between waves = 50m
T = 6.25secs
Speed = 50m/6.25secs
= 8.0m/s
Acceleration is the rate of change of velocity, so can be calculated by:
a = v2 - v1 / t where v2 and v1 are the final and initial velocities of the object respectively and t is the time taken. Therefore the acceleration is:
a = 30 m/s - 20 m/s / 2.0 s = 10 m/s / 2.0 s = 5 m/(s^2)
Hope this helps!
A. The magnitude of the spring force (in N) acting upon the object is 15.9 N
B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²
C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).
<h3>A. How to determine the force </h3>
- Extension (e) = 0.150 m
- Spring constant (K) = 106 N/m
- Force (F) = ?
F = Ke
F = 106 × 0.15
F = 15.9 N
<h3>B. How to determine the acceleration</h3>
- Mass (m) = 0.52 Kg
- Force (F) = 15. 9 N
- Acceleration (a) =?
F = ma
Divide both sides by m
a = F / m
a = 15.9 / 0.52
a = 30.58 m/s²
<h3>C. How to determine the direction of the acceleration vector</h3>
Considering the diagram, we can see that the spring was pulled away from the equilibrium point.
Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.
Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.
Learn more about spring constant:
brainly.com/question/9199238
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Answer:
2.304 × 10^-28 N
Explanation:
Compute the force on each of two electrons when they are seperated in vaccum by a distance corresponding to the approximate size of an ato. (0.100nm)
Solution
The formula to use is
F = K Qq / r^2
Substitute all the parameters
F = 9 × 10^9 × (1.6 × 10^-19)^2 / (0.1 × 10^-9)^2
F = 2.304 × 10^-28 / 1 × 10^-10
F = 2.304 × 10^-18 N
Therefore, the force between each of the electron is 2.304 × 10^-18 N
Answer:
sea water will rise at the equator