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Alex777 [14]
3 years ago
12

The two populations of stars in our galaxy are actually quite similar in many of their characteristics. True False

Physics
1 answer:
stich3 [128]3 years ago
8 0

Answer:

False

Explanation:

The two population of stars in our galaxy are nowhere near similar in many characteristics.

For instance, the stars in the milky way galaxy are about 2/3 of all observable stars. Yes, the populations of stars in the milky way and outside of it are both large, but the population in the milky way galaxy is double that of elsewhere.

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A baseball is hit nearly straight up into the air with a speed of 22 m/s. (a) how high does it go ?
AnnZ [28]

So, this is a problem where the accleration is not provided, since it is implied.  The only acceleration is acceleration due to gravity (9.8 m/s)


The equation we will use for this problem is V^2 =V_{0}^2 + 2a (X-X_0)

V is the final velocity, V₀ is the initial velocity, a is the acceleration, X is the final height, and X₀ is the starting height.


We can assume that the ball starts on the ground since no height is given, so now we plug our numbers in.

We will use 0 as the final velocity, since the ball will stop moving upwards when it is the highest.  We will use -9.8 since that is the acceleration due to gravity and we will use 22m/s as V₀ since that is the starting velocity.

V^2 =V_{0}^2 + 2a (X-X_0)\\0^2 = 22^2 + 2\times-9.8(X-0)\\0=484-19.6x\\-484=-19.6x\\24.69387755 = x\\x\approx24.69


So, the ball will go 24.69 meters up


4 0
3 years ago
Which layer of the sun's atmosphere are you looking at when you look at me in image of the Sun
Hitman42 [59]
The answer is Photosphere.  The photosphere is the lowest layer<span> of the </span>solar<span> atmosphere. It is essentially the </span>solar<span> "surface" that </span>we see<span> when </span>we look<span> at the </span>Sun in "white" light.  It is <span>like a glowing fog, so at a distance, it </span>looks<span> solid, the same way a cloud looks solid from a distance.</span>
7 0
3 years ago
The state of strain at a point is plane strain with εx = ε0, εy = –2ε0, γxy = 0, where ε0 is a positive constant. What is the no
Marat540 [252]

Answer:

The normal strain along an axis oriented 45° from the positive x axis in the clockwise direction is -ε₀/2

Explanation:

Given that

\epsilon_{x}=\epsilon_{o}\\\\\epsilon_{y}=-2\epsilon_{o}\\\\\gamma_{xy}=0\\\\\theta=-45^{o}\\\\\epsilon_{x_{1}}=?

From equation of normal strain in x direction:

\epsilon_{x_{1}}=\epsilon_{x}cos^{2}\theta+\epsilon_{y}sin^{2}\theta+\gamma_{xy{ sin\theta cos\theta

Substituting the values:

\epsilon_{x_{1}}=\epsilon_{o}cos^{2}(-45)-2\epsilon_{o}sin^{2}(-45)+0\\\\\epsilon_{x_{1}}=\frac{\epsilon_{o}}{2}-2\frac{\epsilon_{o}}{2}\\\\\epsilon_{x_{1}}=-\frac{\epsilon_{o}}{2}

6 0
3 years ago
In a physics lab, you measure the vibrational-rotational spectrum of hcl. the estimated separation between absorption peaks is:_
BlackZzzverrR [31]

The appropriate value in blank given is Δf = 5.5 x 10^{11} Hertz.

We have vibrational - rotational spectrum Hydrochloric Acid.

We have to investigate the estimated separation between absorption peaks and fill the blank.

<h3>What is vibrational - rotational spectrum ?</h3>

Rotational–vibrational spectroscopy is a branch of molecular spectroscopy. It deals with the infrared and Raman spectra of molecules in the gaseous phase.

According to the question -

The estimated separation between absorption peaks in the vibrational-rotational spectrum of HCl is denoted by Δf and is equal to -

Δf = 5.5 x 10^{11} Hertz

Hence, the appropriate value in blank given is Δf = 5.5 x 10^{11} Hertz.

To learn more about vibrational-rotational spectrum, visit the link below-

brainly.com/question/18403840

#SPJ4

8 0
2 years ago
So far, you’ve been working with an "ideal" pulley system. How do you think real pulley systems are different, and how would tha
almond37 [142]

Answer:

In an ideal pulley system is assumed as a perfect system, and the efficiency of the pulley system is taken as 100% such that there are no losses of the energy input to the system through the system's component

However, in a real pulley system, there are several means through which energy is lost from the system through friction, which is converted into heat, sound, as well as other forms of energy

Given that the mechanical advantage = Force output/(Force input), and that the input force is known, the energy loss comes from the output force which is then reduced, and therefore, the Actual Mechanical Advantage (AMA) is less than the Ideal Mechanical Advantage of an "ideal" pulley system

The relationship between the actual and ideal mechanical advantage is given by the efficiency of the pulley system as follows;

Efficiency \, \% = \dfrac{AMA}{IMA}  \times 100

Explanation:

8 0
3 years ago
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