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Alex777 [14]
3 years ago
12

The two populations of stars in our galaxy are actually quite similar in many of their characteristics. True False

Physics
1 answer:
stich3 [128]3 years ago
8 0

Answer:

False

Explanation:

The two population of stars in our galaxy are nowhere near similar in many characteristics.

For instance, the stars in the milky way galaxy are about 2/3 of all observable stars. Yes, the populations of stars in the milky way and outside of it are both large, but the population in the milky way galaxy is double that of elsewhere.

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A solenoid of radius 2.0 mm contains 100 turns of wire uniformly distributed over a length of 5.0 cm. It is located in air and c
tankabanditka [31]

Answer:

The magnetic field strength inside the solenoid is 5.026\times10^{-3}\ T.

Explanation:

Given that,

Radius = 2.0 mm

Length = 5.0 cm

Current = 2.0 A

Number of turns = 100

(a). We need to calculate the magnetic field strength inside the solenoid

Using formula of the magnetic field strength

Using Ampere's Law

B=\dfrac{\mu_{0}NI}{l}

Where, N = Number of turns

I = current

l = length

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times100\times2.0}{5.0\times10^{-2}}

B=0.005026=5.026\times10^{-3}\ T

(b). We draw the diagram

Hence, The magnetic field strength inside the solenoid is 5.026\times10^{-3}\ T.

4 0
3 years ago
What are significant figures?
vekshin1
“The term significant figures refers to the number of important single digits (0 through 9 inclusive) in the coefficient of an expression in scientific notation . The number of significant figures in an expression indicates the confidence or precision with which an engineer or scientist states a quantity.”
8 0
3 years ago
Read 2 more answers
A satellite m-500 kg orbits the earth at a distance d 215 km, above the surface of the planet. The radius of the earth is re 6.3
AnnZ [28]

Answer:

7.78 * 10³ m/s

Explanation:

Orbital velocity is given as:

v = √(GM/R)

G = 6.67 * 10^(-11) Nm/kg²

M = 5.98 * 10^(24) kg

R = radius of earth + distance of the satellite from the surface of the earth

R = 2.15 * 10^(5) + 6.38 * 10^(6)

R = 6.595 * 10^(6) m

v = √([6.67 * 10^(-11) * 5.98 * 10^(24)] / 6.595 * 10^(6))

v = √(6.048 * 10^7)

v = 7.78 * 10³ m/s

4 0
3 years ago
Find the resistance of a wire of length 0.65m, 0.2mm and resistivity 3X10^-6 ohm metre.​
const2013 [10]

Answer:

hope this is help full

7 0
3 years ago
A column of water exerts a pressure of 100.Pa and a force of 2.40 N. What is the cross-sectional area of a the column?
salantis [7]

p=f/a ... a=f/p = 2.4/100 = 0.024

7 0
3 years ago
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