Answer:
V = V0 + a t
V = 75 - 9.8 * 3 = 45.6 m/s
Answer:
Recoil speed,
Explanation:
Given that,
Mass of the comet fragment, 
Speed of the comet fragment, 
Mass of Callisto, 
The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

V is recoil speed of Callisto immediately after the collision.

So, the recoil speed of Callisto immediately after the collision is 
Answer:
180 m
Explanation:
Case 1.
U = 40 km/h = 11.1 m/s, V = 0, s = 20 m
Let a be the acceleration.
Use third equation of motion
V^2 = u^2 + 2 as
0 = 11.1 × 11.1 - 2 × a × 20
a = 3.08 m/s^2
Case 2.
U = 220 km/h = 33.3 m/s, V = 0
a = 3.08 m/s^2
Let the stopping distance be x.
Again use third equation of motion
0 = 33.3 × 33.3 - 2 × 3.08 × x
X = 180 m
Answer:
v = 0.33 [m/s]
Explanation:
We must remember that speed is defined as the relationship between the displacement in a given time. In this way, we can propose the following equation.

where:
v = velocity [m/s]
d = displacement = 40 [m]
t = 2 [min] = 120 [s]
Now replacing we have:
![v=40/120\\v=0.33[m/s]](https://tex.z-dn.net/?f=v%3D40%2F120%5C%5Cv%3D0.33%5Bm%2Fs%5D)
Answer:
0.01774 lux
Explanation:
= Polarized light intensity = 36.8 lux
= Angle
Through first filter

Through second filter

intensity of transmitted light is 0.01774 lux